Answer:
Area = 42 in^2
Step-by-step explanation:
here's your solution
=> divide above picture in two parts
=> rectangle and traingle
=> area of rectangle = length* width
=> area of rectangle = (5*6)in.
=> area of rectangle = 30 in^2
=> now, area of traingle = 1/2*base *height
=> area of traingle = 1/2*4*6
=> area of traingle = 12 in^2
=> area of figure = 30 in^2 + 12 in^2
=> Area = 42 in^2
hope it helps
Least is on top, Greatest is on bottom
-24,825
-9.75
-9.7
80
The answer is no. I,m filling in the characters.
Answer:
24 Domain: s>=2 or s<=-2
25. 3x^2 +14x +10
26. x^2 -2x+5
Step-by-step explanation:
24. Domain is the input or s values
square roots must be greater than or equal to zero
s^2-4 >=0
Add 4 to each side
s^2 >=4
Take the square root
s>=2 or s<=-2
25. f(g(x)) stick g(x) into f(u) every place you see a u
f(u) = 3u^2 +2u-6
g(x) = x+2
f(g(x) = 3(x+2)^2 +2(x+2) -6
Foil the squared term
= 3(x^2 +4x+4) +2x+4-6
Distribute
= 3x^2 +12x+12 +2x+4-6
Combine like terms
=3x^2 +14x +10
26 f(g(x)) stick g(x) into f(u) every place you see a u
f(u) = u^2+4
g(x) = x-1
f(g(x) = (x-1)^2 +4
Foil the squared term
= (x^2 -2x+1) +4
= x^2 -2x+5
