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3 years ago

I need help with this, I am confused so please explain to me.

Mathematics

1 answer:

AnnyKZ [126]3 years ago

7 0

Absolute values are more simple than you may think. Absolute values are just the distance that number is from zero. This means that your answer will always be positive.

So for - | - 7 3/5 |, your answer is - 7 3/5 because | - 7 3/5 | is just 7 3/5. But there is a negative on the outside which basically tells you to multiply whatever your answer is by - 1.

You might be interested in

Which of these numbers 3,4,18,111,123,340,345,456,555 are multiples of 33 but not 9?

LUCKY_DIMON [66]

Answer:

4 and 132

Step-by-step explanation:

4 x 33 = 132

the numbers 4 and 132 have nothing to do with 9, no matter what way you look at them

i hope this helps :)

4 0

2 years ago

How are rational functions similar to linear, quadratic, or exponential functions? How are they different? When are these simila

jeyben [28]

Answer:

See explanation below for further details.

Step-by-step explanation:

A rational consist of two real numbers such that:

$\frac{a}{b} =c$

If c is a polynomial with a certain grade, then, both the numerator and the denominator must be also polynomials and the grade of the numerator must be greater than denominator.

If c is linear function, that is, a first order polynomial, then a must be a (n+1)-th polynomial and b must be a n-th polynomial.

Example:

If $a = x^{2}$ and $b = x$ , then:

$c = \frac{x^{2}}{x}$

$c = x$

If c is a quadratic function, that is, a second order polynomial, then a must be a (n+1)-th polynomial and b must be a n-th polynomial.

Example

If $a = 3\cdot x^{3}$ and $b = x$ , then:

$c = \frac{3\cdot x^{3}}{x}$

$c = 3\cdot x^{2}$

But if c is an exponential, both the numerator and the denominator must be therefore exponential function and grade of each exponential function must different to the other.

Example

If $a = 10^{2x}$ and $b = 3\cdot 10^x$ , then:

$c = \frac{10^{2\cdot x}}{3\cdot 10^{x}}$

$c = \frac{1}{3}\cdot 10^{2\cdot x -x}$

$c = \frac{1}{3}\cdot 10^x$

Otherwise, c would be equal to a constant function, that is, a polynomial with a grade 0.

If $a = 5\cdot e^{x}$ and $b = -3\cdot e^{x}$ , then:

Example

$c = \frac{5\cdot e^{x}}{-3\cdot e^{x}}$

$c = -\frac{5}{3}$

It is worth to add that exponential functions can be a linear combination of single exponential function, similar to polynomials.

Example

$5\cdot a^2\cdot x -9$

7 0

3 years ago

Hours (x) 0 1 2 3 4 5

MatroZZZ [7]

The answer is D) 3,404

By putting the table values into the progam DESMOS, and then putting in the formula, the answer will be given- and that answer is 3,404.

5 0

3 years ago

Read 2 more answers

The level of CO2 emissions, f(x), in metric tons, from the town of Fairfax x years after they started recording is shown in the

Temka [501]

1) The average increase in the level of CO2 emissions per year from years 2 to 4 is:
Average=[f(4)-f(2)]/(4-2)=(29,172.15-26,460)/2=2,712.15/2=1,356.075 metric tons. The first is false.

2) The average increase in the level of CO2 emissions per year from years 6 to 8 is:
Average=[f(8)-f(6)]/(8-6)=(35,458.93-32,162.29)/2=3,296.64/2=1,648.32 metric tons. The second is false.

3) The average increase in the level of CO2 emissions per year from years 4 to 6 is:
Average=[f(6)-f(4)]/(6-4)=(32,162.29-29,172.15)/2=2,990.14/2=1,495.07 metric tons. The third is false.

4) The average increase in the level of CO2 emissions per year from years 8 to 10 is:
Average=[f(10)-f(8)]/(10-8)=(39,093.47-35,458.93)/2=3,634.54/2=1,817.27 metric tons. The fourth is true.

Answer: Fourth option: The average increase in the level of CO2 emissions per year from years 8 to 10 is 1,817.27 metric tons.

7 0

2 years ago

What is the slope of a linear that is perpendicular to the line y=-1/2x+5?

Vlada [557]

Step-by-step explanation:

Equation of given line is:

$y = - \frac{1}{2} x + 5 \\ \\ equating \: it \: with \: y =m_1x + c \\ we \: find \: \\ m_1 = - \frac{1}{2} \\ let \: m_2 \: be \: the \: slope \: of \: required \: line \\ \\ \therefore \: m_1 \times m_2 = - 1( \because \: lines \: are \: \perp) \\ \\ \therefore \: - \frac{1}{2} \times m_2 = - 1\\ \\ \therefore \: m_2 = 2 \\$

Thus, the slope of required line is 2.

6 0

2 years ago