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lutik1710 [3]
4 years ago
8

A pyramid has a regular hexagonal base with side links of four and a slant height of six. Find the total area of the pyramid

Mathematics
1 answer:
vova2212 [387]4 years ago
7 0

Area of the Base = 6 * side^2 / 4 * tan (180/6)

Area of the Base = 6 * 16 / 4 * 0.57735

Area of the Base = 96 / 2.3094

Area of the Base = 41.5692387633


Area of 1 Face = 2 * 6 = 12

Area of 6 Faces = 72


Total Area = 41.5692387633 + 72

Total Area = 113.5692387633

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\bf \begin{array}{llll}
term&value\\
-----&-----\\
a_4&9\\
a_5&9+d\\
a_6&(9+d)+d\\
&9+2d\\
a_7&(9+2d)+d\\
&9+3d=\underline{18}
\end{array}\\\\
-------------------------------\\\\
9+3d=18\implies 3d=9\implies d=\cfrac{9}{3}\implies \boxed{d=3}

\bf n^{th}\textit{ term of an arithmetic sequence}\\\\
a_n=a_1+(n-1)d\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
d=\textit{common difference}\\
----------\\
n=7\\
d=3
\end{cases}
\\\\\\
a_7=a_1+(7-1)d\implies 18=a_1+(7-1)3\implies 18=a_1+18
\\\\\\
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Step-by-step explanation:

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