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amid [387]
2 years ago
15

A researcher plans to identify each participant in a certain medical experiment with a code consisting of either a single letter

or a pair of distinct letters written in alphabetical order. What is the lea
Mathematics
1 answer:
Digiron [165]2 years ago
3 0

Answer:

at least 5

Step-by-step explanation:

<u><em>If the question was similar to the one given below </em></u>

A researcher plans to identify each participant in a certain medical experiment with a code consisting of either a single letter or a pair of distinct letters written in alphabetical order. What is the least number of letters that can be used if there are 12 participants, and each participant is to receive a different code?

<em><u>The answer would be as follows</u></em>

If we use 3 letters or any distinct letter as a comma such that 2 are in alphabetical order then we would get

4C2= 6 ways to use these letters and the comma

If we use 4 letters or any distinct letter as a comma such that 2 are in alphabetical order then we would get

5C2= 10 ways to use these letters and the comma

If we use 5 letters or any distinct letter as a comma such that 2 are in alphabetical order then we would get

6C2= 15 ways to use these letters and the comma

We need the least number of the alphabets to assign codes to 12 participants.

So the least number of alphabets is 5 because it can give codes to at least to  12 people .

Pair of alphabets + distinct letter ≥ 12

5 + 1  ≥ 12

6c2  ≥ 12

15  ≥ 12

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Answer:

The probability is 0.0144

Step-by-step explanation:

The probability that x people show up follows a binomial distribution, so it is equal to:

Where n is the number of booked people and p is the probability that a person shows up. Then, the probability that x people show up is:

So, the probability that the number of people who show up will exceed the capacity of the plane is:

P(x>73) = P(74) + P(75)

Where P(74) and P(75) are calculated as:

Finally, P(x>73) is:

P(x>73) = 0.0125 + 0.0019 = 0.0144

3 0
2 years ago
I need lots of help with my homework
Vinil7 [7]
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3 years ago
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