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3 years ago

15

4.10 x 10^-2/ (-2.05 x 10^4)=

1 answer:

kaheart [24]3 years ago

5 0

Answer:

-0.000002

Step-by-step explanation:

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Solve each system of equations by graphing.<br> y=3x-1<br> y=-3x+3

kykrilka [37]

Answer:

Step-by-step explanation:

For y=3x-1 the slope is 3 and the y-intercept is -1

For y=-3x+3 the slope is -3 and the y-intercept is 3

8 0

3 years ago

What is true of a geometric plane?

wel

A geometric plane is two-dimensional. Standing at one point in the plane and picking two directions to travel which are not opposites of one another, any direction of travel on the plane can be obtained by composing these two directions. Since it is two directions, the plane is two-dimensional

6 0

3 years ago

A model of a soccer ball is made up of regular pentagons and hexagons.

Monica [59]

<em>An </em><em>apothem</em><em> is a line from the center of a regular polygon at right angles to any of its sides.</em>

<u>For part A</u>,

We want to find area of pentagon (5 sided figure) given apothem is 1.38 in and side length as 2 inch.

If we look at the picture shown (attached), we can see that a triangle is formed. What is the area of this triangle?

$A=0.5bh\\A=0.5(1)(1.38)\\A=0.69$ square inches

<u><em>How many such triangles are there in a pentagon? 10. So we multiply 0.69 by 10 to get total area of pentagon.</em></u>

Area of Pentagon = $0.69*10=6.9$ square inches.

<u>For part B</u>,

We want to find area of hexagon (6 sided figure) given apothem is 1.73 in and side length as 2 inch.

If we look at the picture shown (attached), we can see that a triangle is formed. What is the area of this triangle?

$A=0.5bh\\A=0.5(1)(1.73)\\A=0.865$ square inches

<em><u>How many such triangles are there in a hexagon? 12. So we multiply 0.865 by 12 to get total area of hexagon.</u></em>

Area of Hexagon = $0.865*12=10.4$ square inches.

ANSWER:

Area of Pentagon is 6.9 square inches.

Area of Hexagon is 10.4 square inches.

5 0

2 years ago

Sonbull [250]

Answer:

$\sqrt{37}$

Step-by-step explanation:

The distance d between a point (m , n ) and a line in the form

Ax + By + C = 0 , is calculated as

d = $\frac{|Am+Bn+C|}{\sqrt{A^2+B^2} }$

Here (m, n ) = (6, 2 ) and

6x - y = - 3 ( add 3 to both sides )

6x - y + 3 = 0 → A = 6, B = - 1, C = 3

d = $\frac{|6(6)+-1(2)+3|}{\sqrt{6^2+(-1)^2} }$

= $\frac{|36-2+3|}{\sqrt{36+1} }$

= $\frac{|37|}{\sqrt{37} }$

= $\frac{37}{\sqrt{37} }$ × $\frac{\sqrt{37} }{\sqrt{37} }$

= $\frac{37\sqrt{37} }{37}$ ← cancel 37 on numerator/ denominator

= $\sqrt{37}$

7 0

2 years ago

Here is a system of equations:

laila [671]

Answer:

y = -10

Step-by-step explanation:

(-7x+3y) - (-7x +10y) =-65 -(-135)

-7x + 3y + 7x -10y = 70

-7y = 70

y = -10

7 0

3 years ago

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