The length of the yard is 25ft.
In order to find this we first need to set up variables for the length and the width. Since we don't know anything about the width, we'll set it as x. Then, we know the length is equal to ten more than three times the width. Since the width is x, we can write the length as 3x + 10. Now we can use the formula for the perimeter of a rectangle to solve for x.
2l + 2w = P
2(3x + 10) + 2(x) = 60
6x + 20 + 2x = 60
8x + 20 = 60
8x = 40
x = 5
Now that we have a value for x, we can plug into the length equation and find the length.
3x + 10
3(5) + 10
15 + 10
25
Answer:
the x-axis is 0,1
the y -axis is -1, - 35
sorry if im rong
Step-by-step explanation:
Answer:
1:c
let x be the distance
12^2=10^(2) + x^(2)
x=6.6332
2.D
length of 2->3 and 2->1 is 90ft, they are perpendicular
by using Pythagorus theorem
the diagonal of the square = square root of the sum of 90^2 +90^2
=127.279ft
3.B
12^2 -6^2 = 10.39ft
Step-by-step explanation:
Answer:
Step-by-step explanation:
we would apply the law of Cosines which is expressed as
a² = b² + c² - 2abCosA
Where a,b and c are the length of each side of the triangle and A is the angle corresponding to a. Likening the expression to the given triangle, it becomes
q² = p² + r² - 2(p × r)CosQ
q² = 12² + 6² - 2(12 × 6)Cos92
q² = 144 + 36 - 2(72)Cos92
q² = 180 - 144 × - 0.0349
q² = 180 + 5.0256
q² = 185.0256
q = √185.0256
q = 13.6 to the nearest integer
