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2 years ago

Find the value of (-15/8 + 1.5) = (15 – 14 3/4)? * -3/2 0 -3/32 O 3/32 O 3/2

Mathematics

1 answer:

sukhopar [10]2 years ago

7 0

Answer:

OKey

Step-by-step explanation:

its 16,2341242112

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Write the inequality that represents the possible values for x

UNO [17]

Answe8 times 8 equal 69 and bla ba

Step-by-step explanation:

3 0

2 years ago

I need helping solving -3z+7=-7-10z

Tpy6a [65]

-3z + 7 = -7 - 10z

Add 10z to both sides

7z + 7 = -7

Subtract 7 from both sides

7z = -14

Divide by 7

Z = -2

8 0

3 years ago

Read 2 more answers

Which is the simplified form of the expression ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript nega

AlekseyPX

Answer:

The option "StartFraction 1 Over 3 Superscript 8" is correct

That is $\frac{1}{3^8}$ is correct answer

Therefore $[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2=\frac{1}{3^8}$

Step-by-step explanation:

Given expression is ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript negative 3 Baseline times ((2 Superscript negative 3 Baseline) (3 squared)) squared

The given expression can be written as

$[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2$

To find the simplified form of the given expression :

$[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2$

$=(2^{-2})^{-3}(3^4)^{-3}\times (2^{-3})^2(3^2)^2$ ( using the property $(ab)^m=a^m.b^m$ )

$=(2^6)(3^{-12})\times (2^{-6})(3^4)$ ( using the property $(a^m)^n=a^{mn}$

$=(2^6)(2^{-6})(3^{-12})(3^4)$ ( combining the like powers )

$=2^{6-6}3^{-12+4}$ ( using the property $a^m.a^n=a^{m+n}$ )

$=2^03^{-8}$

$=\frac{1}{3^8}$ ( using the property $a^{-m}=\frac{1}{a^m}$ )

Therefore $[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2=\frac{1}{3^8}$

Therefore option "StartFraction 1 Over 3 Superscript 8" is correct

That is $\frac{1}{3^8}$ is correct answer

6 0

3 years ago

Read 2 more answers

How many one-to-one correspondences are there between two sets with 5 elements each?

Fittoniya [83]

1st element can be matched with 5
2nd element can be matched with 4
3rd element can be matched with 3
etc.
Total number of correspondences = 5*4*3*2*1 = 120

7 0

2 years ago

Between what two integers does the number square root of 29 lie?

lutik1710 [3]

Your Answer Will Be Between 5 and 6 Because The Square Root Of 29 Is 5.3851 ect

4 0

2 years ago