The coordinates of the pre-image of point F' is (-2, 4)
<h3>How to determine the coordinates of the pre-image of point F'?</h3>
On the given graph, the location of point F' is given as:
F' = (4, -2)
The rule of reflection is given as
Reflection across line y = x
Mathematically, this is represented as
(x, y) = (y, x)
So, we have
F = (-2, 4)
Hence, the coordinates of the pre-image of point F' is (-2, 4)
Read more about transformation at:
brainly.com/question/4289712
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Answer:
A=49 degree
a=13.5
b=11.7
Step-by-step explanation:
Answer:
Step-by-step explanation:
9x + 2y = 24 (A)
y = 6x + 19 ------ > y - 6x = 19 * (-2) -------> -2y + 6x = -38 (B)
(A) + (B)
15x = -14
x = -14/15
y = 6 * (-14/15) + 19 = -28/5 + 19 = 67/5
I got 6x∧2 - 11x + 4
So your answer is correct
Cause I use the box method if that is what u used
