A coffee is sitting on Mr. Hunt's desk cooling. It cools according to the function T=70(0.80)^x+20, where x is the time in minutes and T is the temperature in degree Celsius. WHAT IS THE INITIAL temperature of the coffee
The initial temperature occurs at x = 0
Substitute x = 0 into the expression;
T=70(0.80)^x+20
T =70(0.80)^0+20
Since any value raise to power of zero is 1, hence;
T = 70(1)+20
T = 70+20
T = 90 degree Celsius
Hence the initial temperature of the coffee is 90 degrees
