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3 years ago

Write forty-seven thousandths in standard form.

Mathematics

2 answers:

AnnZ [28]3 years ago

6 0

Answer:

47000 is the answer

Step-by-step explanation:

Eat berries and Creams.

Dmitry_Shevchenko [17]3 years ago

3 0

answer

47000 is the answer

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SUppose the total cost C(x) to manufacture a quantity x of insecticide (in hundreds of liters) is given by

Hitman42 [59]

Answer:

a) $C(x)$ is increasing in two regions: (i) $(+\infty, 8\,s)$ and (ii) $(10\,s,+\infty)$ .

b) $C(x)$ decreases in $(8\,s, 10\,s)$ .

Step-by-step explanation:

Let $C(x) = x^{3}-27\cdot x^{2}+240\cdot x +850$ , where $x$ is the quantity of insecticide, measured in hundreds of liters, and $C(x)$ is the total manufacturing cost as a function of the quantity of the insecticide, measured in US dollars. A possible approach to determine which regions of $C(x)$ are decreasing and increasing by means of the first derivative and graphing tools. The first derivative of the function is:

$C'(x) = 3\cdot x^{2}-54\cdot x+240$ (1)

Please notice that regions where C(x) is increasing has $C'(x) > 0$ , whereas $C'(x) < 0$ when $C(x) < 0$ .

We notice that $C(x)$ is increasing in two regions: (i) $(+\infty, 8\,s)$ and (ii) $(10\,s,+\infty)$ . Besides, $C(x)$ decreases in $(8\,s, 10\,s)$ .

6 0

3 years ago

Nts) in a certain population of voters, 72% of them plan to vote in favor of a new

Ganezh [65]

Answer:

Probability that 10 of them plan to vote against this piece of proposed legislation is 0.0701 or 7.01 %.

Step-by-step explanation:

Consider the event of voting against the piece as success, 'p'. So, voting in favor of the piece is failure and denoted by 'q'.

Given:

Sample size is, $n=25$

Probability of failure is, $q=72\%=0.72$

Therefore, probability of success is, $p=1-q=1-0.72=0.28$

Number of successes is, $x=10$

Now, from Bernoulli's distribution, probability of $x$ successes out of $n$ samples is given as:

$P(X=x)=_{n}^{x}\textrm{C}p^xq^{n-x}$

Here, $n=25,x=10,p=0.28,q=0.72$ . Therefore,

$P(X=10)=_{25}^{10}\textrm{C}(0.28)^{10}(0.72)^{25-10}\\P(X=10)=_{25}^{10}\textrm{C}(0.28)^{10}(0.72)^{15}\\P(X=10)=3.269\times 10^{6}\times 2.962\times 10^{-6}\times 7.244\times 10^{-3}\\P(X=10)=70.142\times 10^{-3}=0.0701=7.01\%$