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3 years ago

HELPPP If Julie makes $20,000 a year, how much will she make in a day?

Mathematics

1 answer:

NNADVOKAT [17]3 years ago

7 0

I’m not sure I would help you if knew

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How many sides does a regular polygon have if it’s central angle is 35 degrees?

umka21 [38]

Answer:

it's not a regular polygon

Step-by-step explanation:

a central angle of a regular polygon is 360/n

360/n=35

n=360/35=10.28

it's not a regular polygon

8 0

3 years ago

Whats the area of the real Bedroom?

Gemiola [76]

Answer:

The answer is 18 cm.

Step-by-step explanation:

Just multiply 6 by 3.

3 0

3 years ago

A factory makes cars at a constant rate. The table shows the number of car’s made for different length’s of time. A manager draw

blagie [28]

Answer:

im not sure if this is right or not but i did the math and got 26

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Find the volume of the largest rectangular box in the first octant with three faces in the coordinate planes and one vertex in t

Tresset [83]

Answer: The volume of largest rectangular box is 4.5 units.

Step-by-step explanation:

Since we have given that

Volume = $xyz$

with subject to $x+2y+3z=9$

So, let $z=\dfrac{9-x-2y}{3}$

So, Volume becomes,

$V=xyz\\\\V=xy(\dfrac{9-x-2y}{3})\\\\V=\dfrac{9xy-x^2y-2xy^2}{3}$

Partially derivative wrt x and y we get that

$9-2x-2y=0\implies 2x+2y=9\\\\and\\\\9-x-4y=0\implies x+4y=9$

By solving these two equations, we get that

$x=3,y=\dfrac{3}{2}$

So, $z=\dfrac{9-x-2y}{3}=\dfrac{9-3-3}{3}=\dfrac{3}{3}=1$

So, Volume of largest rectangular box would be

$xyz=3\times \dfrac{3}{2}\times 1=\dfrac{9}{2}=4.5$

Hence, the volume of largest rectangular box is 4.5 units.

4 0

3 years ago

0 A maker of a certain brand of low-fat cereal bars claims that the average saturated fat content is 0.5 gram. In a random sampl

balandron [24]

Answer:

The first step is to determine the average

$x= \frac{0,6+0,7+ 0,7+0,3+0,4+ 0,5+ 0,4 +0,2}{8}\\\ x= 0,475$

The exercise says it’s a normal distribution: (n=8)

$s^{2}= \frac{1}{n-1} ((0,6.x)^2+2(0,7-x)^2+(0.3-x)^2+2(0.4-x)^2+(0.5-x)^2+(0.2-x)^2)\\\ \frac{1}{7}*0,235 = 0,0336 \\\\ s= 0183$

According to the exercise, the mean is equal to 0,5 then the value of t of the distribution can be obtained

$t= \frac{x-u}{\frac{s}{\sqrt{n} }}\\\ t= \frac{0,475 - 0,5}{0,183}\\\ t= -0,3860$

The variable t has 7 grade to liberty, we calculate the p-value as:

$2* P(t < - 0,3860)= \\\ 2* 0,3554 = 0,7108$

This value is very high, therefore the hypothesis is not rejected

7 0

4 years ago