Answer:
2·(a^2 + b^2) = (a + b)^2
2·a^2 + 2·b^2 = a^2 + 2·a·b + b^2
a^2 + b^2 = 2·a·b
a^2 - 2·a·b + b^2 = 0
(a - b)^2 = 0
a = b
Answer:
the answers to this are x= 1 and y= 9
Answer:
no solution
Step-by-step explanation:
Given
3(x - 3) = 3x , that is
3x - 9 = 3x ( add 9 to both sides )
3x = 3x + 9 ( subtract 3x from both sides )
0 = 9 ← not possible
This indicates the equation has no solution
Answer:
x = 6
y = -6
Step-by-step explanation:
x + y = 0 (Multiply by -1)
x + 9y= -48
-x - y = 0
x + 9y= -48
8y = -48
y = -6
x + y = 0
x - 6 = 0
x = 6
Answer:
The expression
represents the number
rewritten in a+bi form.
Step-by-step explanation:
The value of
is
in term of ![i^{2}[\tex] can be written as, [tex]i^{4}=i^{2}\times i^{2}](https://tex.z-dn.net/?f=i%5E%7B2%7D%5B%5Ctex%5D%20can%20be%20written%20as%2C%20%3C%2Fp%3E%3Cp%3E%5Btex%5Di%5E%7B4%7D%3Di%5E%7B2%7D%5Ctimes%20i%5E%7B2%7D)
Substituting the value,

Product of two negative numbers is always positive.

Now
in term of ![i^{2}[\tex] can be written as, [tex]i^{3}=i^{2}\times i](https://tex.z-dn.net/?f=i%5E%7B2%7D%5B%5Ctex%5D%20can%20be%20written%20as%2C%20%3C%2Fp%3E%3Cp%3E%5Btex%5Di%5E%7B3%7D%3Di%5E%7B2%7D%5Ctimes%20i)
Substituting the value,

Product of one negative and one positive numbers is always negative.

Now
can be written as follows,

Applying radical multiplication rule,


Now,
and 

Now substituting the above values in given expression,

Simplifying,

Collecting similar terms,

Combining similar terms,

The above expression is in the form of a+bi which is the required expression.
Hence, option number 4 is correct.