All categories

2 years ago

Please help asap!!!! will mark brainliest

Mathematics

2 answers:

mafiozo [28]2 years ago

4 0

Answer:

A 9x--12 i hope this helps

dlinn [17]2 years ago

4 0

Answer:

a. 9x-12

Step-by-step explanation:

Perimeter means total length of sides.

So, add (2x-7)+(5x-3)+(2x-2)

9x-12

You might be interested in

Write the value of 83,479

Ann [662]

Eighty three thousand four hundred and seventy nine

6 0

3 years ago

plz help quick. the sum of two numbers is 11. Three times the first number minus the second number is -3. what are the numbers?

Lerok [7]

Answer:

the first number is 2, the second number is 9 :)

Step-by-step explanation:

brainliest? :)

6 0

2 years ago

Suppose you have 5 white, 5 blue and 8 black socks in a drawer. What is the probability that you randomly pick a black sock from

Gnesinka [82]

Answer:

I think it would be 8/18

If it is wrong I'm so sorry

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

6 out of 13 of your

Tasya [4]

Answer:

46.2%

Step-by-step explanation:

6/13 x 100% = 46.1538461538% (rounded to the nearest tenth: 46.2%)

Hope that helps!

5 0

2 years ago

Read 2 more answers

Can someone please explain this to me? Thanks!

Makovka662 [10]

Answer: Choice D

$\displaystyle F\ '(x) = 2x\sqrt{1+x^6}\\\\$

==========================================================

Explanation:

Let g(t) be the antiderivative of $g'(t) = \sqrt{1+t^3}$ . We don't need to find out what g(t) is exactly.

Recall by the fundamental theorem of calculus, we can say the following:

$\displaystyle \int_{a}^{b} g'(t)dt = g(b)-g(a)$

This theorem ties together the concepts of integrals and derivatives to show that they are basically inverse operations (more or less).

So,

$\displaystyle F(x) = \int_{\pi}^{x^2}\sqrt{1+t^3}dt\\\\ \displaystyle F(x) = \int_{\pi}^{x^2}g'(t)dt\\\\ \displaystyle F(x) = g(x^2) - g(\pi)\\\\$

From here, we apply the derivative with respect to x to both sides. Note that the $g(\pi)$ portion is a constant, so $g'(\pi) = 0$

$\displaystyle F(x) = g(x^2) - g(\pi)\\\\ \displaystyle F \ '(x) = \frac{d}{dx}[g(x^2)-g(\pi)]\\\\\displaystyle F\ '(x) = \frac{d}{dx}[g(x^2)] - \frac{d}{dx}[g(\pi)]\\\\ \displaystyle F\ '(x) = \frac{d}{dx}[x^2]*g'(x^2) - g'(\pi) \ \text{ .... chain rule}\\\\$

$\displaystyle F\ '(x) = 2x*g'(x^2) - 0\\\\ \displaystyle F\ '(x) = 2x*g'(x^2)\\\\ \displaystyle F\ '(x) = 2x\sqrt{1+(x^2)^3}\\\\ \displaystyle F\ '(x) = \boldsymbol{2x\sqrt{1+x^6}}\\\\$

Answer is choice D

5 0

2 years ago

Read 2 more answers