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Sauron [17]
2 years ago
9

Which expressions are equivalent to 12r-5

Mathematics
1 answer:
ANEK [815]2 years ago
5 0

The expression 12r - 5 are equivalent to 6(2r+(-1))+1 and -4(2+(-3r))+3 option (A) and (B) are correct.

<h3>What is an expression?</h3>

It is defined as the combination of constants and variables with mathematical operators.

We have an expression:

= 12r - 5

A) 6(2r+(-1))+1

= 12r + 6(-1) + 1

= 12r -5

B) -4(2+(-3r))+3

= -8 -4(-3r) + 3

= -5 + 12r

or

= 12r - 5

Thus, the expression 12r - 5 are equivalent to 6(2r+(-1))+1 and -4(2+(-3r))+3 option (A) and (B) are correct.

Learn more about the expression here:

brainly.com/question/14083225

#SPJ1

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Which set of rectangular coordinates describes the same location as the polar coordinates (6sqrt 2, 3pi/4)
Sonja [21]
Polar coordinates=<span>(6sqrt 2, 3pi/4)=(r, theta)→r=6 sqrt 2, theta=3pi/4
Rectangular coordinates=(x,y)=?

x=r cos theta=(6 sqrt 2) cos(3pi/4)=(6 sqrt 2)(-sqrt 2 / 2)
x=-3 (sqrt 2)^2=-3(2)→x=-6

y=r sin theta=(6 sqrt 2) sin (3pi/4)=(6 sqrt 2)(sqrt 2 / 2)
y=3 (sqrt 2)^2=3(2)→y=6

Rectangular coordinates of the point = (x,y) =(-6,6)

Answer: Option a. (-6,6) </span>
8 0
2 years ago
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Andreas93 [3]
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Now you have:

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3 years ago
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oee [108]

Answer:

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Step-by-step explanation:

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Since the diagonals bisect each other it implies that AM=AO and NP=AP

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