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elixir [45]
3 years ago
8

Point C is the center of the circle. The measure of angle ACB is 12x – 7. Arc ADB measures 10x – 7. Find the value of x.

Mathematics
1 answer:
Anna35 [415]3 years ago
6 0
We are asked to solve for the value of x given that the center is the point C and the ∠ACB is 12x-7 while the given arc is equal to 10x-7. To solve this problem, we need to remember that the summation of angle ACB and angle ADB is equal to 360°. Hence, the solution is shown below:
∠ACB + ∠ADB = 360°
12X - 7 + 10X -7 = 360 , combine same term such as:
22x - 14 = 360 , transpose -14 to the right side such as:
22x = 360 + 14
22x = 374 , divide both sides bu 22
22x/ 22 = 374 / 22
x = 17

The answer to this problem is 17 and this is the value of x.

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A simple random sample of 36 men from a normally distributed population results in a standard deviation of 10.1 beats per minute
Katyanochek1 [597]

Answer:

Step-by-step explanation:

Given that:

sample size n = 36

standard deviation = 10.1

level of significance ∝ = 0.10

The null hypothesis and the alternative hypothesis can be computed as follows:

H_0 : \sigma = 10

H_1 : \sigma \neq 10

The test statistics can be computed as follows:

X^2 = \dfrac{(n -1)s^2 }{\sigma ^2}

X^2 = \dfrac{(36 -1)10.1^2 }{10^2}

X^2 = \dfrac{(35)102.01 }{100}

X^2 = \dfrac{3570.35 }{100}

X^2 =35.704

degree of freedom = n - 1 = 36 - 1 = 35

Since this test is two tailed .

The P -value can be determined by using the EXCEL FUNCTION ( = 2 × CHIDIST(35.7035, 35)

P - value = 2 × 0.435163515

P - value = 0.8703      ( to four decimal places)

Decision Rule : To reject the null hypothesis if  P - value is less than the 0.10

Conclusion: We fail to reject null hypothesis ( accept null hypothesis) since p-value is greater than 0.10 and we conclude that there is sufficient claim that the normal range of pulse rates of adults given as 60 to 100 beats per minute resulted to a standard deviation of 10 beats per minute.

3 0
3 years ago
This pencil cup is made out of plastic. It is 5 inches tall and has a radius of 1.75 inches. How many square inches of plastic w
Dmitry [639]

Answer:

To make the cup 64.57 square inches of plastic were used.

Step-by-step explanation:

A cup has the format of a cylinder with a open top. The surface area of the cup is given by the area of it's base (a circle) and the area of it's walls, wich can be seen as rectangle where the width is the length of the circle at the base and the height is the height of the cylinder. So we have:

area of the base = pi*r^2 = 3.14*(1.75)^2 = 3.14*3.0625 = 9.616 square inches

area of the walls = 2*pi*r*h = 2*3.14*(1.75)*5 = 54.95 square inches

surface area of the cup = area of the base + area of the walls = 9.616 + 54.95

surface area of the cup = 64.57 square inches

To make the cup 64.57 square inches of plastic were used.

3 0
3 years ago
I need some help with geometry.
motikmotik

Answer:

x = 17, angle 1 and 2 = 45

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
Suppose that salaries for recent graduates of one university have a mean of $25,700 with a standard deviation of $1350. Using Ch
sergeinik [125]

Answer:

75% of the data will reside in the range 23000 to 28400.

Step-by-step explanation :

To find the range of values :

We need to find the values that deviate from the mean. Since we want at least 75% of the data to reside between the range therefore we have,

1 - \frac{1}{k^2} =\frac{75}{100}

Solving this, we would get k = 2 which shows the value one needs to find lies outside the range.

Range is given by : mean +/- (z score) × (value of a standard deviation)  

⇒ Range : 25700 +/- 2 × 1350

⇒ Range : (25700 - 2700) to (25700 + 2700)

Hence, 75% of the data will reside in the range 23000 to 28400.

3 0
3 years ago
Find x<br> a) 21 √2<br> b)7<br> c)21 √2/2<br> d)21 √3/2
fgiga [73]

Answer:

C

Step-by-step explanation:

Use the sine ratio in the left, right triangle to find the common side to both triangles and the exact values

sin60° = \frac{\sqrt{3} }{2} , cos45° = \frac{1}{\sqrt{2} } , thus

sin60° = \frac{opposite}{hypotenuse} = \frac{opp}{7\sqrt{3} } = \frac{\sqrt{3} }{2} ( cross- multiply )

2 × opp = 21 ( divide both sides by 2 )

opp = \frac{21}{2}

Now consider the right triangle on the right, using the cosine ratio

cos45° = \frac{adjacent}{hypotenuse} = \frac{\frac{21}{2} }{x} = \frac{1}{\sqrt{2} } ( cross- multiply )

x = \frac{21}{2} × \sqrt{2} = \frac{21\sqrt{2} }{2} → C

5 0
2 years ago
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