The graph of f(x) = 0.5sin(4x) is sketched below
<h3>Graph of trigonometric functions </h3>
From the question, we are to sketch the graph of the given trigonometric function.
The given trigonometric function is
f(x) = 0.5sin(4x)
The graph of f(x) = 0.5sin(4x) is sketched below
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We have to factor becasue
area=legnth times width
area=4x^2+28x+49
area=(2x+7)(2x+7)
area=(2x+7)^2
legnth =width
we arent' given area so we can't solve
but, , since it is a squaer room, legnth=width so √area=legnth=width
Answer:
reflection, rotation, and translation.
Answer:
51.63m^3
Step-by-step explanation:
The figure is made up of a rectangle, triangle and a semi circle
Area of the figure = Area of triangle + rectangle + semicircle
Area of the triangle = 1/2 * base * height
Area of the triangle = 1/2 * 3 * 5
Area of the triangle = 15/2
Area of the triangle = 7.5m^3
Area of the rectangle = Length * Width
Area of the rectangle = 6 * 5
Area of the rectangle = 30m^2
Area of the semicircle = πr²/2
Area of the semicircle = π(3)²/2
Area of the semicircle = 3.14(9)/2
Area of the semicircle = 3.14 * 4.5
Area of the semicircle = 14.13m^2
The area = 30 + 14.13+7.5
Area of the figure = 51.63m^3