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exis [7]
3 years ago
8

The graph below could be the graph of which exponential function? 5 A. F(x) = 3 . (1.7)* B. F(x) = 3 • (0.7)* C. F(x) = 3. (-1.7

)​

Mathematics
1 answer:
Marrrta [24]3 years ago
6 0

Answer:

C

Step-by-step explanation:

use ur cal

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Sales at LL Boutique decreased 10% this month compared to last month. If sales this month were $103,581, what were the sales (in
Art [367]

Answer:

Step-by-step explanation:

(103,581) • (%110)

= (103,581) • (1.10)

=  $113,939.1

7 0
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Find c. Round to the nearest tenth
sergeinik [125]

Answer:

c = <u>0.5 cm</u>

Step-by-step explanation:

Using the Sine rule in the triangle, then

=  ( cross- multiply )

c × sin105° = 2 × sin15° ( divide both sides by sin105°

c =  ≈ 0.5 cm ( to the nearest tenth )

8 0
3 years ago
4 x 4/12=<br> Sheeeeeeeeeeeeeeeesh
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2 years ago
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From a random sample of size 18, a researcher states that (11.1, 15.7) inches is a 90% confidence interval for mu, the mean leng
alexandr402 [8]

Complete Question

From a random sample of size 18, a researcher states that (11.1, 15.7) inches is a 90% confidence interval for mu, the mean length of bass caught in a small lake. A normal distribution was assumed. Using the 90% confidence interval obtain:

a. A point estimate of \mu and its 90% margin of error.

b. A 95% confidence interval for \mu.

Answer:

a

\= x  = 13.4   .   E = 2.3

b

10.7 <  \mu < 16.1

Step-by-step explanation:

From the question we are told that

  The sample size is  n = 18

  The 90% confidence interval is  (11.1, 15.7)

Generally the point estimate of  \mu is mathematically  evaluated  as

       \= x  = \frac{11.1 + 15.7 }{2}

=>    \= x  = 13.4

Generally the margin of error is mathematically evaluated  as

     E = \frac{15.7 - 11.1}{2 }

=> E = 2.3

  From the question we are told the confidence level is  90% , hence the level of significance is    

      \alpha = (100 - 90 ) \%

=>   \alpha = 0.10

Generally from the normal distribution table the critical value  of  \frac{\alpha }{2} is  

   Z_{\frac{\alpha }{2} } =  1.645

Generally the equation for the lower limit of the confidence interval is  

      \= x  -  Z_{\frac{\alpha }{2} } * \frac{s}{\sqrt{18} } = 11.1

=> 13.4   -  0.3877 s  = 11.1

=>  s = 5.932

  From the question we are told the confidence level is  95% , hence the level of significance is    

      \alpha = (100 - 95 ) \%

=>   \alpha = 0.05

Generally from the normal distribution table the critical value  of  \frac{\alpha }{2} is  

   Z_{\frac{\alpha }{2} } =  1.96

Generally the margin of error is mathematically represented as  

      E = Z_{\frac{\alpha }{2} } *  \frac{\sigma }{\sqrt{n} }

=>    E =  1.96 *  \frac{5.932}{\sqrt{18} }

=>    E =  2.7      

Generally 95% confidence interval is mathematically represented as  

      \= x -E <  \mu <  \=x  +E

=>    13.4  -  2.7  <  \mu < 13.4  +   2.7

=>    10.7 <  \mu < 16.1

3 0
3 years ago
The table of values represents a quadratic function. What is the average rate of change for f(x) from x = 0 to x = 10 ? Enter yo
Elena-2011 [213]
By definition we have that the average rate of change is given by:
 AVR = (f (x2) - f (x1)) / (x2 - x1)
 Substituting the values we have:
 AVR = (204 - (-6)) / (10 - 0)
 Rewriting we have:
 AVR = (204 + 6) / (10 - 0)
 AVR = 210/10
 AVR = 21
 Answer:
 
the average rate of change for f (x) from x = 0 to x = 10 is:
 
AVR = 21
8 0
3 years ago
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