Are a rational expression and its simplified forms equivalent

frank and max and sara are given £800 to share between their ages frank is 9 max is 13 and sara is 18 how much do they each get?

Oksana_A [137]

They would each get 266 and some change

3 0

4 years ago

Read 2 more answers

What is the slope of the following table?

Bess [88]

Answer:

$- \frac{1}{2}$

c)

Step-by-step explanation:

the x rate of change is +2 and the y rate of change if -1. slope is always y over x, therefore, do exactly that. put y (-1) over x (2). thus gett in your answer of the slope.

5 0

3 years ago

Triangle ABC is shown below.

inna [77]

Answer:

the answer is 14 C

Step-by-step explanation:

just took the test?

3 0

3 years ago

Bob the snail travels 48 cm at 16 cm per minute how long did it take him please explain

OleMash [197]

Answer:

it toke hoh 3 minutes to trave

Step-by-step explanation:

since the given is 48 cm (distance) and 16cm per minute ( speed )

the equation for that is distance over speed

so ... 48÷16 is equal to 3

so it took bob the snail 3 minutes to travel 48 cm

8 0

3 years ago

A computer chess game and a human chess champion are evenly matched. They play ten games. Find probabilities for the following e

AleksAgata [21]

Answer:

(a) The probability that each of them win five games is 0.2461.

(b) The probability that the computer wins seven games is 0.1172.

(c) The probability that the human wins at least 7 games is 0.1711.

Step-by-step explanation:

Let the random variable X = the human wins a chess game.

The probability that the human wins a game is, P (X) = p = 0.50.

The number of games played by the computer and the human is, n = 10.

The random variable $X\sim Bin(n = 10,p=0.50)$

The probability distribution of the Binomial random variable X is:

$P (X=x)={n\choose x}p^{x}(1-p)^{n-x}={10\choose x}(0.50)^{x}(1-0.50)^{10-x}$

(a)

If both the computer and the human wins five games each then the probability of the human winning 5 games is:

$P (X=5)={10\choose 5}(0.50)^{5}(1-0.50)^{10-5}\\=252\times 0.03125\times0.03125\\=0.246094\\\approx 0.2461$

Thus, the probability that each of them win five games is 0.2461.

(b)

If the computer wins 7 games then the number of games won by the human is, 10 - 7 = 3.

P (Computer winning 7 games) = P (Human winning 3 games)

The probability that the human wins 3 games is:

$P (X=3)={10\choose 3}(0.50)^{3}(1-0.50)^{10-3}\\=120\times 0.125\times0.0078125\\=0.1171875\\\approx 0.1172$

Thus, the probability that the computer wins seven games is 0.1172.

(c)

Compute the probability that the human wins at least 7 games as follows:

$P(X\geq 7)=P(X=7)+P(X=8)+P(X=9)+P(X=10)\\={10\choose 7}(0.50)^{7}(1-0.50)^{10-7}+{10\choose 8}(0.50)^{8}(1-0.50)^{10-8}\\+{10\choose 9}(0.50)^{9}(1-0.50)^{10-9}+{10\choose 10}(0.50)^{10}(1-0.50)^{10-10}\\=0.1172+0.044+0.009+0.0009\\=0.1711$

Thus, the probability that the human wins at least 7 games is 0.1711.

5 0

4 years ago