End time12:33 .elapsed time 33 min what is start time

Mathematics

2 answers:

Alex17521 [72]4 years ago

7 0

The start time would be 12:00.

Amanda [17]4 years ago

7 0

12:00 because you take away the elapsed time ( the time it took ) from the end time to give you the start time.

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Find the length of x, then the length of y, to the nearest tenth of a metre.

ladessa [460]

Answer:

x=9.717

y=18.275

Step-by-step explanation:

First solve for x and then use x to help you solve for y

5 0

3 years ago

bette drives at 60 mph for 2 and a half hours and 75 mph for 1 and a half hours. What is her average rate of speed?

andrezito [222]

There are a couple of ways to think about this.

1) Weight the speed by the time and compute the weighted average.
(60*2.5 + 75*1.5)/(2.5 + 1.5) = 65.625
Her average rate of speed is 65.625 mph.

2) Consider distance and time.
distance = speed * time
distance₁ = speed₁ * time₁
distance₂ = speed₂ * time₂
total distance = distance₁ + distance₂
total time = time₁ + time₂
And the average speed is given by
average speed = (total distance)/(total time)

Using the above formulas, we have
distance₁ = 60 mi/h * 2.5 h = 150 mi
distance₂ = 75 mi/h * 1.5 h = 112.5 mi
total distance = 150 mi + 112.5 mi = 262.5 mi

total time = 2.5 h + 1.5 h = 4.0 h

average speed = (262.5 mi) / (4.0 h) = 65.625 mi/h

Bette's average rate of speed is 65.625 mph.

7 0

3 years ago

The glass container is filled to a height of 2.25 inches. What percent of the container is filled with sand?

Makovka662 [10]

The complete question in the attached figure

Part A) How much sand is currently in the container?
[sand currently in the container]=(5)*(4 1/2)*(2.25)-----> (5)*(4.5)*(2.25)
[sand currently in the container]=50.625 in³

the answer Part a) is 50.625 in³

Part B) How much more sand could the container hold before?
[sand could the container hold before]=[5*4.5*3]-[50.625]
[sand could the container hold before]=[67.5]-[50.625]------> 16.875 in³

the answer Part B) is 16.875 in³

Part C) What percent of the container is filled with sand?
the volume of container is [5*4.5*3]=67.5 in³
the volume filled with sand=50.625 in³
therefore
if 100%----------------> 67.5 in³
X---------------------> 50.625 in³
X=(50.625*100)/67.5=75 %

the answer Part C) is 75%

4 0

4 years ago

OX and OY are two straight lines which intersect at an acute angle of 60°. OX = 4.5cm and OY = 5cm . The point M is on OX such t

Neko [114]

Therefore the point P is at 3.46 cm from O and it lies on the angle bisector of ∠XOY

<h3>What is an Angle Bisector ?</h3>

The ray that bisects the angle into half is called Angle Bisector.

It is given that ∠XOY = 60 degree

the length of OX = 4.5 cm

OY =5 cm

The point M is on OX such that

OM = 2 MX

so The M is at 3 cm from O

The point P lies in the acute angle such that the distance between point P and OX and OY is always same and at 3 cm from M

According to the angle bisector theorem converse states that if a point is in the interior of an angle and is at equal distance from the sides then it lies on the bisector of that angle.

As it can be seen from the image that a point equidistant from the rays , at 3 cm from M will be at

By Pythagoras Theorem

3² +3² = OP²

OP = 2 $\sqrt{3}$ = 3.46 cm from O