Answer:
A
Step-by-step explanation:
for the relation to be a function then each value of x in the domain must map to exactly one unique value of y in the range
this is the case for A
in B : 3 → 2 and 3 → 8 ← not a function
in C : - 2 → 5 and - 2 → 7 ← not a function
in D : 2 → 2 and 2 → 3 and 3 → 3 and 3 → 2 ← not a function
B^-2 / b^-3 = b^(-2-(-3) = b^1 = b
answer is d
Answer:
x(x+6)(x-4)
Step-by-step explanation:
They all have x in it, which means we can factor out x first.
x(x^2 + 2x -24)
Now we can factor out the inside doing algebra.
Since 6 multiplied by -4 gives us -24 and adding them gives us 2, 6 and -4 works. This means that we can factor out (x+6) and (x-4).
We still have to multiply the x from the beginning, giving us a final equation of
x(x+6)(x-4).
10+(1/2)+10+(1/2) 42
------------------------- = -------
2 2
21+15=36
