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3 years ago

NEED HELP ASAP PLEASE

Mathematics

1 answer:

katen-ka-za [31]3 years ago

5 0

Answer:

Pretty sure its 40

Step-by-step explanation:

There is only 3 odd numbers on a 6 sided dice (1, 3, 5) and you would just divide 120 and 3

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dimaraw [331]

The first one is 17 13/15 the second one is 22 1/20

4 0

3 years ago

Please help me I need an answer

Mumz [18]

1) 2/4 = 1/4 + 1/4
2) 4/6 = 1/6 + 1/6 + 1/6 + 1/6
3) 3/5 = 1/5 + 1/5 + 1/5
4) 3/3 = 1/3 + 1/3 + 1/3
5) 7/8 = 1/8 + 1/8 + 1/8 + 1/8 + 1/8 + 1/8 + 1/8
6) 6/2 = 1/2 + 1/2 + 1/2 + 1/2 + 1/2 + 1/2
7) 5/6 = 1/6 + 1/6 + 1/6 + 1/6 + 1/6
8) 9/5 = 1/5 + 1/5 + 1/5 + 1/5 + 1/5 + 1/5 + 1/5 + 1/5 + 1/5
9) 8/3 = 1/3 + 1/3 + 1/3 + 1/3 + 1/3 + 1/3 + 1/3 + 1/3
10) 1/2 * 8 = 8/2 = 4

11) Unit fractions are fractions where its numerators are 1 and its denominators are positive integer. example: 1/2 ; 1/3 ; 1/4

12) D.) 5/2 = 5 * 1/2

7 0

3 years ago

What are the potential solutions of In(x2 - 25) = 0?

Paha777 [63]

Answer:

$x=\pm\sqrt{26}$

Step-by-step explanation:

$ln(x^2-25)=0$

$e^{ln(x^2-25)}=e^0$

$x^2-25=1$

$x^2=26$

$x=\pm\sqrt{26}$

7 0

3 years ago

the length of a rectangle is 2 inches less than twice its width. If the perimeter of the rectangle is 74 inches, what is the are

schepotkina [342]

If the width is w and the length is l, then 2w-2=l and 2w+2l=72 (using the perimeter equation). Plugging 2w-2 in for l, we get 2w+(2w-2)*2=72 and 6w-4=72. Adding 4 to both sides, we get 6w=76. After that, we divide both sides by 6 to get 74/6=w. Since l=2w-2=136/6, we get (136/6)(74/6)=656.75=area

5 0

3 years ago

It is assumed that the test results for a class follow a normal distribution with a mean of 78 and a standard deviation of 36. I

HACTEHA [7]

Answer:

0.7143

- You know the minimum possible grade of the student

- You want to find out the probability that that grade which is greater than 72 is also greater than 84

- Expect the answer to be 0.7143

- The explanation/steps is given below

- The answer seems (and is) reasonable. You only created a new lower limit.

Step-by-step explanation:

Distribution Type: Normal

Mean: 78

Standard deviation: 36

Range of marks: [78 - 36], [78 + 36] = [42 to 114]

If you know that a student's grade is greater than 72, what is the probability that it's greater than 84?

In this case, the full probability level is between 72 and the upper limit of 114 (instead of between 42 and 114). First, find the fraction of this probability.

[114 - 72] ÷ [114 - 42] = 42/72 = 0.5833

So, the probability of a student's mark falling between 72 and 114 is 0.5833.

Now making this a whole interval, 114 - 72 = 42

What fraction of this interval of 42 will bear marks between 84 and 114?

[114 - 84] = 30

30/42 = 0.7143

Because of the first part of the question "If you know (are sure) that a student's grade is greater than 72...", your answer stops at 0.7143, since 72 was used as the lower limit.

8 0

2 years ago