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dusya [7]
3 years ago
7

What is the mass of a cookbook

Computers and Technology
1 answer:
tatiyna3 years ago
6 0

Answer:

it varies on the size of the cookbook

Explanation:

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Why is it useful for students to practice the MLA and APA citation methods?
notka56 [123]

Answer:

Citing or documenting the sources used in your research serves three purposes:

It gives proper credit to the authors of the words or ideas that you incorporated into your paper.

It allows those who are reading your work to locate your sources, in order to learn more about the ideas that you include in your paper.

5 0
2 years ago
Please tell fast plzzzzzz.​
lana [24]

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True

Explanation:

4 0
2 years ago
Place the optical discs in the increasing order of storage capacity.<br><br> UDO<br> CD<br> DVD
romanna [79]
<h2>Hello!</h2>

The answer is:

  1. CD
  2. DVD
  3. UDO
<h2>Why?</h2>

Optical disks are circular disks used as storage for binary data usually made of polycarbonate. The data is stored in the disc using a laser machine and accessed using a laser diode illuminating the data path in an optical disc drive.

CD: Compact Discs are the most basic optical disk used today, with only a capacity that goes from 0.7 GB (700 MB) to 0.84 GB (840 MB).

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UDO: Ultra Density Optical have high capacity storage that goes from 30 GB (30000 MB) to about 60 GB (6000 MB).

Have a nice day!

4 0
3 years ago
When a piece of shiny silver jewelry gets tarnished, what has happened?
makvit [3.9K]
A
because if you leave certain metals in the rain they tarnish or rust. think about how if you leave a bike in the rain for too long it will start to rust on the metal parts
6 0
3 years ago
This program is to compute and write to a file the GPA for student scores read from an input file. The point values of the grade
VARVARA [1.3K]

Answer:

#Take input from the user

filename=input('Enter name of input file: ')

total_units=0#Total number of units for a student

total_score=0#Total score of a student

#Assign a score to each grade. I have reduced 0.33 for each grade. Change here if you need to

grade={'A':4.0,'A-':3.67,'B+':3.34,'B':3.01,'B-':2.68,'C+':2.35,'C':2.02,'C-':1.69,'D+':1.36,'D':1.03}

try:

with open(filename,"r") as input_file:#Open the file for input(reading)

output_file=open("GPA_output.txt","w") #Create and open GPA_output.txt if it doesn't exist for writing

for student_record in input_file:#read from input file

if("," in student_record):#if there is a , that means this is the student name

student_name=student_record.strip('\n')#Remove \n from student name

continue

else:

if(" " in student_record):#If a line contains spaces then its the student's grades for a course

student=student_record.split(" ")#Split to find the coursename, units and grade

#student[0]=coursename student[1]=units student[2]=grade

total_units+=int(student[1])#Calculate total units for 1 student

total_score+=int(student[1])*grade[student[2].strip('\n')]#Find the total score of a student

#grade[student[2]] will lookup for the score that we initialized earlier

#if student has a grade as A then this will look up as grade['A'] which will return 4

#Find the total score as product of this grade and units for this course

continue

else:

if(total_units>0):#Check if score has been calculated for a student earlier

print("in")

GPA=total_score/total_units#Calculate the GPA

output_file.write("%-26s%.2f\n" % (student_name, GPA))#Write the GPA and Student Name in the required format

total_units=0#reset the units

total_score=0#reset the score

if(total_units>0):#Essential for the case when the file doesn't end with a new line(Check if total_units is not 0) which means a record is pending

#to be written to the file

GPA=total_score/total_units#Calculate the GPA

output_file.write("%-26s%.2f\n" % (student_name, GPA))#Write the GPA and Student Name in the required format

total_units=0#reset the units

total_score=0#reset the score

input_file.close()#Close the input file

output_file.close()#Close the output file

except IOError as e:

print("Problem in Opening the required file")#Print a message if file cannot be opened

Explanation:

The program has been tested for all 3 scenarios mentioned i.e.

a. If the file ends without \n

b. If the file ends with 2 \n

c. If the file ends with 1 \n

PS: The Program will run irrespective of how it ends. Even if there are many \n at the end of file, the program will be fine.

3 0
3 years ago
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