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3 years ago

Can somebody please help me with this

Mathematics

1 answer:

pickupchik [31]3 years ago

6 0

Answer:

13.35

Step-by-step explanation:

you multiply 89 times 15

then divide that with 100

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On a coordinate plane, how are the locations of the points (1 , -5) and (-1 , 5) related

KengaRu [80]

Answer:

They are a transformation

Step-by-step explanation:

Checked using desmos graphing

8 0

3 years ago

Find the angel x in d diagram above with a well structured solution.<br><br>Thanks

Tom [10]

Step-by-step answer:

Please refer to attached image.

1. Quad PQRS is cyclic (all vertices on the same circle), so opposite angles are supplementary, meaning

that

angles QPS and QRS are supplementary =>

QPS+QRS=180 =>

QRS = 180 - 74 = 106

2. Triangle RSQ is isosceles with RS=RQ =>

angles RSQ and RQS are congruent.

3. Angle RSQ = (180 - 106) /2 = 74 / 2 = 37

4. QP is a diameter => angle QSP is a right-angle.

5. From (3) and (4) above,

angle RSP = 37+90 = 127

6. Since PQRS is cyclic, angles RQP and RSP are supplementary =>

RQP+RSP = 180 =>

x + 127 = 180 =>

x = 180 - 127 = 53 degrees.

5 0

3 years ago

A sailboat travels a distance of 2 1/2 miles in 1/6 of an hour. Which complex fraction represents the unit rate in miles per hou

Nikitich [7]

At first glance, prolly c

3 0

3 years ago

What is A decreased by 20% and then increased by 20% of that? Please show your work.

umka21 [38]

$Answer: \\ A - 20\%A = A - 0.2A = 0.8A \\ 0.8A + 20\%0.8A = 0.8A + 0.2 \times 0.8A = 0.8 + 0.16A = 0.96A$

8 0

3 years ago

A parabola has a focus of F(2, -0.5) and a directrix of y=-1.5 P(x,y) represents any point on the parabola, while D(x, -1.5) rep

prohojiy [21]

The sketch of the parabola is attached below

We have the focus $(a,b) = (2, -0.5)$
The point $P(x,y)$
The directrix, c at $y=-1.5$

The steps to find the equation of the parabola are as follows

Step 1
Find the distance between the focus and the point P using Pythagoras. We have two coordinates; $(2, -0.5)$ and $(x,y)$ .
We need the vertical and horizontal distances to find the hypotenuse (the diagram is shown in the second diagram).
The distance between the focus and point P is given by
$\sqrt{ (x-a)^{2}+ (y-b)^{2} }$

Step 2
Find the distance between the point P to the directrix $c$ . It is a vertical distance between y and c, expressed as $y-c$

Step 3
The equation of parabola is then given as
$\sqrt{ (x-a)^{2}+ (y-b)^{2} }$ = $y-c$
$(x-a)^{2}+ (y-b)^{2}= (y-c)^{2}$ ⇒ substituting a, b and c
$(x-2)^{2}+ (y--0.5)^{2} = (y--1.5)^{2}$
$(x-2)^{2}+ (y+0.5)^{2}= (y+1.5)^{2}$ ⇒Rearranging and making $y$ the subject gives

$y= \frac{ x^{2} }{2} -2x+1$

7 0

4 years ago