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irakobra [83]
2 years ago
14

Can somebody please help me with this

Mathematics
1 answer:
pickupchik [31]2 years ago
6 0

Answer:

13.35

Step-by-step explanation:

you multiply 89 times 15

then divide that with 100

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Pls just answer number 19 I will mark brainliest
bonufazy [111]
2 feet 7 inches.

5 feet - 2 feet is 3 feet
3 inches - 8 inches is - 5 inches.

just take the 5 inches from 3 feet to get 2 feet 7 inches.
7 0
3 years ago
Does (7, 8) make the equation y = x + 5 true?
NNADVOKAT [17]

Answer:

..

Step-by-step explanation:

no the correct point would be (7,12)

7x1=7

7+5=12

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3 years ago
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Jasmine runs 13kilometers and 76 minutes. how long woukd it take to run 1 kilometers​
k0ka [10]

Answer:

It would take her 5.85 minutes to run 1 kilometer.

Step-by-step explanation:

76/13= 5.846

5 0
3 years ago
What is the geometric mean of 3 and 24?​
Contact [7]

Answer:

for GM, you find out the square root of the product of the numbers provided.

= \sqrt{3 \times 24}  \\  =  \sqrt{72} \\  = 6 \sqrt{2}

since 72 can be broken down into the product of 36 and 2. 6 being the square root of 36 comes out, leaving 2 behind.

7 0
3 years ago
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find the parametric equations for the line of intersection of the two planes z = x + y and 5x - y + 2z = 2. Use your equations t
Kaylis [27]

Answer:

You didn't give the points in which you want the parametric equations be filled, but I have obtained the parametric equations, and they are:

x = (1/3 + t)

y = (-1/3 - 7t)

z = -6t

Step-by-step explanation:

If two planes intersect each other, the intersection will always be a line.

The vector equation for the line of intersection is given by

r = r_0 + tv

where r_0 is a point on the line and v is the vector result of the cross product of the normal vectors of the two planes.

The parametric equations for the line of intersection are given by

x = ax, y = by, and z = cz

where a, b and c are the coefficients from the vector equation

r = ai + bj + ck

To find the parametric equations for the line of intersection of the planes.

x + y - z = 0

5x - y + 2z = 2

We need to find the vector equation of the line of intersection. In order to get it, we’ll need to first find v, the cross product of the normal vectors of the given planes.

The normal vectors for the planes are:

For the plane x + y - z = 0, the normal vector is a⟨1, 1, -1⟩

For the plane 5x - y + 2z = 2, the normal vector is b⟨5, -1, 2⟩

The cross product of the normal vectors is

v = a × b =

|i j k|

|1 1 -1|

|5 -1 2|

= i(2 - 1) - j(2 + 5) + k(-1 - 5)

= i - 7j - 6k

v = ⟨1, -7, -6⟩

We also need a point on the line of intersection. To get it, we’ll use the equations of the given planes as a system of linear equations. If we set z = 0 in both equations, we get

x + y = 0

5x - y = 2

Adding these equations

5x + x + y - y = 2 + 0

6x = 2

x = 1/3

Substituting x = 1/3 back into

x + y = 0

y = -1/3

Putting these values together, the point on the line of intersection is

(1/3, -1/3, 0)

r_0= (1/3) i - (1/3) j + 0 k

r_0​​ = ⟨1/3, -1/3, 0⟩

Now we’ll plug v and r_0​​ into the vector equation.

r = r_0​​ + tv

r = (1/3)i - (1/3)j + 0k + t(i - 7j - 6k)

= (1/3 + t) i - (1/3 + 7t) j - 6t k

With the vector equation for the line of intersection in hand, we can find the parametric equations for the same line. Matching up r = ai + bj + ck with our vector equation,

r = (1/3 + t) i + (-1/3 - 7t) j + (-6t) k

a = (1/3 + t)

b = (-1/3 - 7t)

c = -6t

Therefore, the parametric equations for the line of intersection are

x = (1/3 + t)

y = (-1/3 - 7t)

z = -6t

3 0
3 years ago
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