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2 years ago

9

Austin invested $200 in an account paying an interest rate of 6.1% compounded quarterly. Assuming no deposits or withdrawals are

made, how much money, to the nearest ten dollars, would be in the account after 15 years?

1 answer:

juin [17]2 years ago

4 0

Answer:

jump on the beat of the gospel drums

Step-by-step explanation:

You might be interested in

Pls help me with A and B

Talja [164]

Answer:

Part A-19 hamburgers

Part B- 38 sliders

Step-by-step explanation:

Since quarter pound of meat is 0.25, divide 4.75/0.25 to get 19 hamburgers.

Since a slider needs half as much meat as a hamburger, it needs 0.125 pounds of meat. So, divide 4.75/0.125 to get 38 sliders.

3 0

2 years ago

I don't really know what to do for this one.

Colt1911 [192]

Let, Price of a shirt = x
Price of a Jeans = y

Equations would be: 4x + 3y = 150
x + 2y = 70
x = 70-2y

Substitute it into first equation,
4(70-2y) + 3y = 150
280 - 8y + 3y = 150
-5y = -130
y = 130/5
y = 26

Substitute it into 2nd equation,
x + 2(26) = 70
x = 70-52
x = 18

So, Cost of a Shirt = $18 & Cost of a Jeans = $26

Hope this helps!

3 0

2 years ago

there are fifty five people thirty four are female and twenty one are what is the percentage of male

Natali5045456 [20]

Answer:

38.2%

Step-by-step explanation:

3 0

3 years ago

David wants to make a box plot showing histeam's points for the year. The median score was 7, first quartile was 4, and third qu

vichka [17]

A dot above 7, 4, 10, 2, and 20. Draw a box around the median, first quartile, and and the third quartile. Then connect the box to the minimum and maximum by drawing a line. Should look like this:

8 0

3 years ago

Find the value of the variable y, where the sum of the fractions 6/(y+1) and y/(y-2) is equal to their product.

Blizzard [7]

Answer:

The answer is

$y = 3$

$y = - 4$

Step-by-step explanation:

We must find a solution where

$\frac{6}{y + 1} + \frac{y}{y - 2} = \frac{6}{y + 1} \times \frac{y}{y - 2}$

Consider the Left Side:

First, to add fraction multiply each fraction on the left by it corresponding denomiator and we should get

$\frac{6}{y + 1} \times \frac{y - 2}{y - 2} + \frac{y}{y - 2} \times \frac{y + 1}{y + 1}$

Which equals

$\frac{6y - 12}{(y -2) (y + 1)} + \frac{ {y}^{2} + y }{(y - 2)(y + 1)}$

Add the fractions

$\frac{y {}^{2} + 7y - 12 }{(y - 2)(y + 1)} = \frac{6}{y + 1} \times \frac{y}{y - 2}$

Simplify the right side by multiplying the fraction

$\frac{6y}{(y + 1)(y + 2)}$

Set both fractions equal to each other

$\frac{6y}{(y + 1)(y - 2)} = \frac{ {y}^{2} + 7y - 12}{(y + 1)(y - 2)}$

Since the denomiator are equal, we must set the numerator equal to each other

$6y = {y}^{2} + 7y - 12$

$= {y}^{2} + y - 12$

$(y + 4)(y - 3)$

$y = - 4$

$y = 3$

6 0

2 years ago

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