Can anyone please help me ? It’s due today :(
1 answer:
Answer:
The new coordinates are:
- A' (6, 24)
- B'(12, 12)
- C'(-12, 6)
Please check the attached graph.
Step-by-step explanation:
We know that when an object is dilated by a scale factor, it gets reduced, stretched, or remains the same, depending upon the value of the scale factor.
If the scale factor > 1, the image is enlarged
If the scale factor is between 0 and 1, it gets shrunk
If the scale factor = 1, the object and the image are congruent
Given the vertices of the triangle in the diagram
A (1, 4)
B(2, 2)
C(-2, 1)
In our case:
- Scale Factor K = 6
Rule to calculate the dilation by a scale factor 6 centered at the origin
P(x, y) → P'(6x, 6y)
Here, P'(6x, 6y) ) is the image of P(x, y).
- It means the coordinates of the image can be determined by multiplying the coordinates of the original point by 6.
Thus,
A (1, 4) → A'(6(1), 6(4)) → A'(6, 24)
B(2, 2) → B'(6(2), 6(2)) → B'(12, 12)
C(-2, 1) → C'(6(-2), 6(1)) → C'(-12, 6)
Therefore, the new coordinates are:
- A' (6, 24)
- B'(12, 12)
- C'(-12, 6)
Please check the attached graph.
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Answer:
f(x) is quadratic. g(x) and h(x) are linear.
Step-by-step explanation:
So we have the three functions:
Linear functions are polynomials in which the highest degree is 1.
Quadratic functions are polynomials in which the highest degree is 2.
And exponential functions usually have a variable in the exponent (e.g. 2^x).
For f(x), the highest degree is 2. Thus, f(x) is a quadratic function.
For g(x), the highest degree is 1 and there are no variables in the exponent. Thus, g(x) is a linear function.
Similarly, for h(x), the highest degree is 1 and there are no variables in the exponents, so h(x) is also a linear function.