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anastassius [24]
3 years ago
5

Mrs. Ramos has 37 pictures hanging up in her classroom. She has 24 pictures in the hallway. 18 of those pictures are of students

. How many are not of students?
Mathematics
1 answer:
Vikentia [17]3 years ago
7 0

Answer: 43

Step-by-step explanation: 37 + 24 = 61

61 - 18 = 43

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The points plotted below satisfy a polynomial equation. What type of extreme value does the graph have in the part that is visib
bezimeni [28]
Hi!

The graph shows an A) Maximum

A Maximum value appears in a graph when all other values of the polynomial are smaller in value i.e. are under it in an X-Y plot. This is expressed mathematically as:

There is a maximum if for a given x*: f(x*) ≥ f(x) for all x. 

In the graph, you can clearly see that there is a value that is higher than all the others, so this value is a Maximum. 
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What are the coordinates of the point? A coordinate grid with a dot placed in the second quadrant. The dot is to the left of pos
GenaCL600 [577]
We know that the point is in Q II.  Thus, the x-coordinate of this point will be negative and the y-coordinate will be positive.

The y-coordinate is essentially given, and is y=4.
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The coordinates of the point are (-2, -4).

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3 years ago
Which expression is not equivalent to 6^3/6^6?<br><br> a: 1/6^2<br><br> or<br><br> b: 1/6^3
Angelina_Jolie [31]

Answer:

<h2>A. 1/6^2</h2>

Step-by-step explanation:

6^3/6^6 = 1/216

1/6^2 = 1/36 ≠ 1/216

1/6^3 = 1/216

7 0
3 years ago
Read 2 more answers
Find the area of the part of the plane 3x 2y z = 6 that lies in the first octant.
gavmur [86]

The area of the part of the plane 3x 2y z = 6 that lies in the first octant  is  mathematically given as

A=3 √(4) units ^2

<h3>What is the area of the part of the plane 3x 2y z = 6 that lies in the first octant.?</h3>

Generally, the equation for is  mathematically given as

The Figure is the x-y plane triangle formed by the shading. The formula for the surface area of a z=f(x, y) surface is as follows:

A=\iint_{R_{x y}} \sqrt{f_{x}^{2}+f_{y}^{2}+1} d x d y(1)

The partial derivatives of a function are f x and f y.

\begin{aligned}&Z=f(x)=6-3 x-2 y \\&=\frac{\partial f(x)}{\partial x}=-3 \\&=\frac{\partial f(y)}{\partial y}=-2\end{aligned}

When these numbers are plugged into equation (1) and the integrals are given bounds, we get:

&=\int_{0}^{2} \int_{0}^{3-\frac{3}{2} x} \sqrt{(-3)^{2}+(-2)^2+1dxdy} \\\\&=\int_{0}^{2} \int_{0}^{3-\frac{3}{2} x} \sqrt{14} d x d y \\\\&=\sqrt{14} \int_{0}^{2}[y]_{0}^{3-\frac{3}{2} x} d x d y \\\\&=\sqrt{14} \int_{0}^{2}\left[3-\frac{3}{2} x\right] d x \\\\

&=\sqrt{14}\left[3 x-\frac{3}{2} \cdot \frac{1}{2} \cdot x^{2}\right]_{0}^{2} \\\\&=\sqrt{14}\left[3-\frac{3}{2} \cdot \frac{1}{2} \cdot x^{2}\right]_{0}^{2} \\\\&=\sqrt{14}\left[3.2-\frac{3}{2} \cdot \frac{1}{2} \cdot 3^{2}\right] \\\\&=3 \sqrt{14} \text { units }{ }^{2}

In conclusion,  the area is

A=3 √4 units ^2

Read more about the plane

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5 0
1 year ago
An above-ground swimming pool in the shape of a cylinder has a diameter of
Xelga [282]

Step-by-step explanation:

18-6=12

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