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3 years ago

3 (x – 4) = 2x + 6 solve for x

Mathematics

1 answer:

Illusion [34]3 years ago

3 0

Answer:

Step-by-step explanation:

3 (x – 4) = 2x + 6 Remove the brackets

3x - 12 = 2x + 6 Add 12 to both sides.

3x - 12 + 12 = 2x + 6 + 12 Combine

3x = 2x + 18 Subtract 2x from both sides

3x-2x = 2x-2x + 18 Combine

x = 18

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Choose the inequality that represents the following graph.

dusya [7]

Answer:

Step-by-step explanation:

The solid circle at - 3 indicates that x can be equal to - 3

The arrow pointing left indicates the values of x are less than - 3

Then

x ≤ - 3 → B

6 0

3 years ago

Write the equation of the parabola that has its x-intercepts at (1+<img src="https://tex.z-dn.net/?f=%5Csqrt%7B5%7D" id="TexForm

VladimirAG [237]

Answer:

$y=2x^2-4x-8$

Step-by-step explanation:

Factored form of a parabola

$y=a(x-p)(x-q)$

where:

p and q are the x-intercepts.
a is some constant.

Given x-intercepts:

(1+√5, 0)
(1-√5, 0)

Therefore:

$\implies y=a(x-(1+\sqrt{5}))(x-(1-\sqrt{5}))$

$\implies y=a(x-1-\sqrt{5})(x-1+\sqrt{5})$

To find a, substitute the given point (4, 8) into the equation and solve for a:

$\implies a(4-1-\sqrt{5})(4-1+\sqrt{5})=8$

$\implies a(3-\sqrt{5})(3+\sqrt{5})=8$

$\implies4a=8$

$\implies a=2$

Therefore, the equation of the parabola in factored form is:

$\implies y=2(x-1-\sqrt{5})(x-1+\sqrt{5})$

Expand so that the equation is in standard form:

$\implies y=2(x^2-x+\sqrt{5}x-x+1-\sqrt{5}-\sqrt{5}x+\sqrt{5}-5)$

$\implies y=2(x^2-x-x+\sqrt{5}x-\sqrt{5}x+\sqrt{5}-\sqrt{5}+1-5)$

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2 years ago

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Genrish500 [490]

Answer:

Step-by-step explanation:

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3 years ago

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AleksAgata [21]

Answer:

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Step-by-step explanation:

Gradient is the derivative of the curve:

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substitute for x :

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Answer:

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