Answer:
The measure of angle KLM is 62°
Step-by-step explanation:
* Lets revise the properties of the rhombus
- The rhombus has 4 equal sides in length
- Every two opposite angles are equal in measure
- The two diagonals bisect each other
- The two diagonals perpendicular to each other
- The two diagonals bisect the vertices angles
* Lets solve the problem
∵ JKLM is a rhombus
∴ m∠MJK = m∠KLM ⇒ opposite angles in the rhombus
∵ JL and KM are diagonals in the rhombus and intersect each
other at N
∴ JL bisects ∠MJK
∴ m∠KJL = m∠MJN
∵ m∠KJL = (2x + 5)°
∵ m∠MJN = (3x - 8)°
∴ 2x + 5 = 3x - 8 ⇒ subtract 2x from both sides
∴ 5 = x - 8 ⇒ add 8 to both sides
∴ 13 = x
∴ The value of x = 13
∵ m∠KJL = (2x + 5)° ⇒ substitute the value of x
∴ m∠KJL = 2(13) + 5 = 26 + 5 = 31°
∵ m∠KJL = 1/2 m∠MJK
∴ m∠MJK = 2 m∠KJL
∴ m∠ MJK = 2 × 31° = 62°
∵ m∠MJK = m∠KLM ⇒ opposite angles in the rhombus
∴ m∠KLM = 62°
Answer:
Rui will reach his lowest altitude after diving for 10 seconds
Step-by-step explanation:
In the quadratic equation y = ax² + bx + c, the coordinates of the lowest or the highest point is (h, k), where
- h =
and k = y at x = h
In the given question
∵ d(x) =
x² - 10 x
∵ d represents his altitude in meters after x seconds
→ Compare it with the form above to find a and b
∴ a =
and b = -10
∵ h =
→ Substitute the values of a and b in the rule to find h
∴ h =
= 10
∴ h = 10
∵ h is the x-coordinate of the lowest point
∴ The time of the lowest altitude is 10 seconds
∴ Rui will reach his lowest altitude after diving for 10 seconds
8. B, X=21
9. D X=16, Y=10
10. D X=7
Answer:
x=2/3 or x=−1/2
Step-by-step explanation:
6x²−x=2
6x²−x−2=2−2
6x²−x−2=0
(3x−2)(2x+1)=0
3x−2=0 or 2x+1=0
x=2/3 or x=−1/2
283 rounded to the nearest ten is 280
When rounding to the nearest ten look at the number to the right of the place you are rounding. In this case it is the 3. If the number is 5 or higher you go up to the nearest ten. If the number is lower than 5 like it is in this number you round down to the nearest ten.