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3 years ago

Difference between Virtual reality and Augmented reality

Computers and Technology

2 answers:

Murrr4er [49]3 years ago

6 0

I belive virtual is something you can see over technology and augmented reality means your physically there

marishachu [46]3 years ago

5 0

Virtually: Over the internet, Not present in person

Argumented Reality: in person, arguing, face to face

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wooooooooo helll yeaaa made it to ACE baby now road to whatever next, lil present imma be doing You tube soon soo ideas will be

vichka [17]

Answer:yo bro I don’t know but the answer is b

Explanation:

8 0

3 years ago

Read 2 more answers

You decide to buy some stocks for a certain price and then sell them at another price. Write a program that determines whether o

ser-zykov [4K]

Answer:

#here is code in python.

#read number of shares

num_share = int(input("Enter number of shares:"))

#read purchase price

buy_p = float(input("Enter purchase price:"))

#read sell price

sell_p = float(input("Enter sale price:"))

#total buying cost

buy_cost=buy_p*1.03*num_share

#total selling cost

sell_cost=sell_p*0.97*num_share

#if net profit

if(sell_cost>buy_cost):

print("After the transaction, you made " +str(sell_cost-buy_cost)+ " dollars.")

#if net loss

else:

print("After the transaction, you lost " +str(buy_cost-sell_cost)+ " dollars.")

Explanation:

Read the total number of shares from user.Then read buying price of a share and selling price of a share.Then calculate total buying cost including commission.Calculate total selling cost excluding the commission.If total buying cost is greater than total selling cost the print the profit else print the loss in the transaction.

Output:

Enter number of shares:10

Enter purchase price:10

Enter sale price:10

After the transaction, you lost 6.0 dollars.

4 0

3 years ago

Consider the following statements: struct supplierType { string name; int supplierID; }; struct paintType { supplierType supplie

Romashka [77]

Answer:

The answer is "supplierType"

Explanation:

Description of the code:

In the given program two structure is defined, that is "supplierType and paintType", in which "supplierType" structure two-variable name and "supplierID" is defined, that datatype is "String and integer".
In the next step, "paintType" is declared, in which "supplierType" object supplier is created, in which two string variable "color and paintID" are defined, in which "supplierType" data type is supplied.

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4 years ago

What are the pieces of information that describe the appearance of a cells content

Allushta [10]

Answer:

Information about the parts of a cell, its location and role will help describe the appearance of a cell's content.

Organelles are cell structures that include the nucleus, cytoplasm, cell membrane among others. One can view these using a light microscope.

1. Cell Membrane is a fluid mosaic. It is the outer boundary of the cell.

2.Cytoplasm is the fluid inside the cell. It is located between the nucleus and the cell membrane.

3.Nucleus is the control center of the cell and is located at the center.

4 0

3 years ago

Computer Networks - Queues

lyudmila [28]

Answer:

the average arrival rate \lambda in units of packets/second is 15.24 kbps

the average number of packets w waiting to be serviced in the buffer is 762 bits

Explanation:

Given that:

A single channel with a capacity of 64 kbps.

Average packet waiting time $T_w$ in the buffer = 0.05 second

Average number of packets in residence = 1 packet

Average packet length r = 1000 bits

What are the average arrival rate \lambda in units of packets/second and the average number of packets w waiting to be serviced in the buffer?

The Conservation of Time and Messages ;

E(R) = E(W) + ρ

r = w + ρ

Using Little law ;

r = λ × T_r

w = λ × T_w

r / λ = w / λ + ρ / λ

T_r =T_w + 1 / μ

T_r = T_w +T_s

where ;

ρ = utilisation fraction of time facility

r = mean number of item in the system waiting to be served

w = mean number of packet waiting to be served

λ = mean number of arrival per second

T_r =mean time an item spent in the system

T_w = mean waiting time

μ = traffic intensity

T_s = mean service time for each arrival

the average arrival rate \lambda in units of packets/second; we have the following.

First let's determine the serving time T_s

the serving time T_s $= \dfrac{1000}{64*1000}$

= 0.015625

now; the mean time an item spent in the system T_r = T_w +T_s

where;

T_w = 0.05 (i.e the average packet waiting time)

T_s = 0.015625

T_r = 0.05 + 0.015625

T_r = 0.065625

However; the mean number of arrival per second λ is;

r = λ × T_r

λ = r / T_r

λ = 1000 / 0.065625

λ = 15238.09524 bps

λ ≅ 15.24 kbps

Thus; the average arrival rate \lambda in units of packets/second is 15.24 kbps

b) Determine the average number of packets w waiting to be serviced in the buffer.

mean number of packets w waiting to be served is calculated using the formula

w = λ × T_w

where;

T_w = 0.05

w = 15238.09524 × 0.05

w = 761.904762

w ≅ 762 bits

Thus; the average number of packets w waiting to be serviced in the buffer is 762 bits

4 0

3 years ago