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BartSMP [9]
3 years ago
15

Which of the following equations is NOT an example of inverse variation?

Mathematics
1 answer:
astraxan [27]3 years ago
5 0
Your answer is going to be f
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Given that x +y=180, p +q =180, and p=x show that y =q
makvit [3.9K]
Showin that x=p the. The only way that y=q is because the others are the same say x=179 the y has to =1 and then p=179 so q has to equal =1
8 0
3 years ago
Find the coordinates of the transformed image when the pre-image is reflected over the line x=2
zepelin [54]
A’= (10,1)
B’= (8,1)
C’= (9,5)
D’= (7,5)

hope this helps!
8 0
3 years ago
Divide 48 in the ratio of 2 : 4
dimaraw [331]
The correct answer is 8

7 0
3 years ago
walnut grower estimates from past records that if 20 trees are planted per acre, then each tree will average 60 pounds of nuts p
laila [671]

Answer:

5 trees should be planted to maximize the yield per acre,

The maximum yield would be 1250

Step-by-step explanation:

Given,

The original number of trees per acre = 20,

Average pounds of nuts by a tree = 60,

Let x be the times of increment in number of trees,

So, the new number of trees planted per acre = 20 + x

∵ for each additional tree planted per acre, the average yield per tree drops 2 pounds,

So, the new number of pounds of nut = (60 - 2x)

Thus, the total yield per acre,

Y(x) = (20+x)(60-2x)

Differentiating with respect to t ( time ),

Y'(x) = (20+x)(-2) + 60 - 2x = -40 - 2x + 60 - 2x = 20 - 4x

Again differentiating with respect to t,

Y''(x) = -4

For maxima or minima,

Y'(x) = 0

⇒ 20 - 4x = 0

⇒ 20 = 4x

⇒ x = 5,

For x = 5, Y''(x) = negative,

Hence, Y(x) is maximum for x = 5,

And, maximum value of Y(x) = (20+5)(60 - 10) = 25(50) = 1250,

i.e. 5 trees should be planted to maximize the yield per acre,

and the maximum yield would be 1250 pounds

4 0
3 years ago
The cost to print digital photos at a local store is
snow_tiger [21]
<h2>The cost is same for both the options if we purchase 27 photos</h2>

Step-by-step explanation:

   Cost of a photo at a local store is $0.25 per photo. This cost can be modeled to be linear in number of photos as C_{1}(x)=0.25x.

   Cost of photos purchased online is $0.15 per photo. However there is a shipping cost of $2.70. This can also be modeled to be linear in number of photos as C_{2}(x)=2.70+0.15x.

   Let us assume both costs are the same if we purchase n photos.

So, C_{1}(n)=C_{2}(n)

0.25n=2.70+0.15n

0.10n=2.70

n=27

∴ On purchasing 27 photos, cost for both the options is the same.

5 0
3 years ago
Read 2 more answers
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