You do distance over time to get the rate, so you'd do 27/2= 13.5mph then divide that in half since you're asking for the distance traveled in half that hour so you do 13.5/2 and you get 6.75 miles traveled in half and hour.
2) Add 0.1 to both sides. v/2.2=7.5
Then multiply by 2.2 on both sides.
v=16.5
4) Subtract 1.9 from both sides. -1.3g=-13
Divide both sides by -1.3
g=10
6) Add 1.4 to both sides. -12.9=-3d
Divide -3 on both sides.
d=4.3
Answer:
first do:
60mph * 4 hours= 240mi
Let D = the distance the passenger train has to
travel to catch the freight train
Start a stopwatch when the passenger train leaves
Let t = the time on the stopwatch when they meet
Equation for freight train:
d-240=60t
Equation for passenger train:
d=100t
all together:
100t-240=60t
we can do 100t-60t because they both have (t)= 40t
40t=240 *now divide 240 by 40= 6
THEN do:
D= 100mph x 6= 600mi
They will meet 600 mi from the station
to check:
d-240=60t x 6
600-240= 360
60 x 6= 360
360=360
