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poizon [28]
4 years ago
11

Lydia baked a total of 144 chocolate chip cookies and peanut butter treats for Valentine's Day. Initially, the ratio of chocolat

e chip cookies to peanut butter treats was 5:3. After Lydia's friends ate 2/5 of her chocolate chip cookies and some of her peanut butter treats, the cookies outnumbered the treats 6 to 1. How many peanut butter treats did she have left?
Please show your work with your answer!
Mathematics
2 answers:
yaroslaw [1]4 years ago
4 0
Let:
 x: chip cookies
 y: peanut butter
 We have the following system of equations:
 x + y = 144
 x / y = 5/3
 We solve the system of equations:
 Step 1:
 x + y = 144
 y = (3/5) x
 Step 2:
 x + (3/5) x = 144
 (8/5) x = 144
 x = (5/8) * (144) = 90
 Step 3:
 y = (3/5) x
 y = (3/5) * (90) = 54
 Lydia's friends ate 2/5 of her chocolate chip cookies:
 x '= (2/5) * (90) = 36
 the cookies outnumbered the treats 6 to 1
 x '/ y' = 6/1
 Clearing y '
 y '= (1/6) * x'
 y '= (1/6) * 36
 y '= 6
 Answer:
 she had left 6 butter treats
andre [41]4 years ago
3 0
Let x be the chocolate chip cookies, so the peanut butter treats will be 144-x.
We know that the cookies and the treats are in a ratio of 5:3, so:\frac{cookies}{treats} = \frac{5}{3} = \frac{x}{144-x}
Now we can solve for x:
\frac{5}{3} = \frac{x}{144-x}
5(144-x)=3x
720-5x=3x
8x=720
x= \frac{720}{8}
x=90

We now know Lydia has 90 chocolate chip cookies, and 144-x=144-90=54 peanut butter treats.

Then, Lydia's friend ate \frac{3}{5} of her cookies, so her friend ate \frac{2}{5} (90)=36 cookies. Therefore, Lydia has 90-36=54 cookies left.
Now we can calculate the total amount of baked goods after her friend ate the cookies:
144-54=90
Therefore, our remainder treats will be:
90-x

We also now that after her friend ate 54 cookies and some treats, the new ratio is 6:1, and that's all we need to set up our new equation and solve it to find how many treats she ate:
\frac{cookies}{treats} = \frac{6}{1} = \frac{54}{90-x}
6(90-x)=54
540-6x=54
6x=486
x= \frac{486}{6}
x=81

Finally, if she ate 81 out 90 treats, we can conclude the Lydia has left with 9 peanut butter treats.


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Line l is parallel to line e in the figure below.
agasfer [191]

Answer: The correct option are as follows;

(1) The triangles are similar because corresponding sides are congruent

(2) The triangles are similar because alternate interior angles are congruent

(3) In the similar triangles, Angle 3 and Angle 6 are corresponding angles

Step-by-step explanation: Please refer to the picture attached for details.

The line i and line e has been drawn and marked as parallel lines. Also two transversal lines m and n have been drawn to intersect in the region between the parallel lines to form two triangles (as shown in the picture).

From the information given, where line e intersects with line n we have angle 1, and where line e intersects with line m we have angle 3, and then the third angle is angle 2.

Furthermore, where line l intersects line m we have angle 6, and where line l intersects line n is angle 4. Also in this second triangle, the third angle is 5.

Upon close observation we would see that Angle 6 is equal to Angle 3, since the transversal m has cut across both parallel lines l and e. Similarly Angle 4 is equal to Angle 1 since the transversal n has cut across parallel lines l and e. Having that Angles 3 and 1 are congruent to Angles 6 and 4, we can conclude that the value of the third angle in one triangle is equal to the that of the third in the second triangle, that is, Angle 2 equals Angle 5. Also, if the angles are similar and the lines l and e are parallel, then the lines formed in both triangles are equal.

So our conclusions are;

The interior angle are alternate angles (Angles 3 and 6, Angles 1 and 4), and the third interior angles are Opposite (Angles 2 and 5 {Opposite angles are equal})

8 0
3 years ago
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Divide -3x^3-2x^2-x-2 by x-2
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Let's do this by Briot-Ruffini


First: Find the monomial root


x - 2 = 0

x = 2


Second: Allign this root with all the other coeficients from equation

Equation = -3x³ - 2x² - x - 2

Coeficients = -3, -2, -1, -2

2 | -3 -2 -1 -2


Copy the first coeficient


2 | -3 -2 -1 -2

-3


Multiply him by the root and sum with the next coeficient


2.(-3) = -6

-6 + (-2) = -8


2 | -3 -2 -1 -2

-3 -8


Do the same


2.(-8) = -16

-16 + (-1) = -17


2 | -3 -2 -1 -2

-3 -8 -17


The same,


2.(-17) = -34

-34 + (-2) = -36


2 | -3 -2 -1 -2

-3 -8 -17 -36


Now you just need to put the "x" after all these numbers with one exponent less, see


2 | -3x³ - 2x² - 1x - 2

-3x² - 8x - 17 -36


You may be asking what exponent -36 should be, and I say:


None or the monomial. He's like the rest of this division, so you can say:


(-3x³ - 2x² - x - 2)/(x - 2) = -3x² - 8x - 17 with rest -36 or you can say:

(-3x³ - 2x² - x - 2)/(x - 2) = -3x² - 8x - 17 - 36/(x - 2)


Just divide the rest by the monomial.

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The value of sin(2x) is \frac{120}{169}

Explanation:

Given that tan x =\frac{12}{5}

The formula for sin(2x) is \sin (2 x)=2 \sin x \cos x

Since, \tan x=\frac{o p p}{a d j}

Also, it is given that tan x =\frac{12}{5}

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To find the hypotenuse, let us use the pythagoras theorem,

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Now, substituting these values in the formula for sin 2x, we get,

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