These points are unclear to read could you maybe upload a picture of the problem?
<h3>
Answer: B. All real numbers</h3>
Work Shown:
2(3c+3) < 6c+9
6c+6 < 6c+9 .... distribute
6c+6-6c <6c+9-6c .... subtract 6c from both sides
6 < 9 ... note the c terms go away entirely
We're left with a statement that is always true since 6 is always less than 9 regardless of what value of c we pick. So there are infinitely many solutions. Any real number can replace c to get a true statement.
Answer:
45,489.6 pounds!
Step-by-step explanation:
To solve this problem, first we need to find the volume of the pool.
We know that the dimensions of the pool are:
Width = 9ft
Length = 18ft
Height = 54in = 4.5 ft
So the volume of the pool is:
Volume = Width x Length x Height = 9ftx18ftx4.5ft = 729ft^3
We know that one cubic foot of water weights about 62.4 pounds. To fill the pool, we will need 729ft^3 of water.
So the weight of the water is:
Weight = 729ft^3 x 62.4 pounds/ft = 45,489.6 pounds!
Answer:
-19
Step-by-step explanation:
-3+10- (-4) × (-5)+(-6)
-3+10+4 × (-5)-6
4×(-5) = -20 -3+10-20-6 = -19
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Answer:
No.
There's no congruence theorem or statement that proves that 2 triangles with 2 sides and a non-included angle are congruent to each other.
Step-by-step explanation:
The triangles given, ∆ABC and ∆CYZ both have a non-included angle and two sides given that are congruent to each other.
However, this alone is not enough to prove that both ∆s are congruent to each other because there is also possiblity of another ∆ that will have the same two equal sides and a non-included angle as any of the 2, and can thereby have different shape and size.
There's also no congruency statement that proves that two triangles with congruent two sides and a non-included angle are congruent to each other.
Therefore, the information to us is not enough.
