Answer:
The pressure difference is 25.8kPa while the force exerted on the window by air pressure is 3.02 kN
Explanation:
Using the Bernoulli's equation
Here
- Pin-Pout is the pressure difference which is to be calculated.
- ρ is the density of air whose value is 1.29 kg/m^3
- vin is the velocity of air inside which is 0 m/s
- vout is the velocity of air outside which is 200 m/s
Substituting values in the above equation yields
So the pressure difference is 25.8kPa.
As force is given by
Here
- ΔP is the pressure difference calculated above
- A is the area of the window given as
Now force is
So the force exerted on the window by air pressure is 3.02 kN