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3 years ago

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Newton's First and Second Laws of Motion:Question 3Kepler-10b, the first confirmed terrestrial extrasolar planet, is about 564 l

ight-years away from Earth. Kepler-10b is a superearth, meaning it is a little larger and more massive than Earth. It has a surface gravity that is 1.53 times that of Earth. How much thrust would be required to accelerate a 5,000-kg spacecraft 2.13 m/s2 from the surface of Kepler-10b

1 answer:

OleMash [197]3 years ago

8 0

Answer:

F = 85696.5 N = 85.69 KN

Explanation:

In this scenario, we apply Newton's Second Law:

$Unbalanced\ Force = ma\\Upthrust - Weight\ of\ Space\ Craft = ma\\F - W = ma\\F - mg = ma\\F = m(g + a)\\$

where,

F = Upthrust = ?

m = mass of space craft = 5000 kg

g = acceleration due to gravity on surface of Kepler-10b = (1.53)(9.81 m/s²)

g = 15.0093 m/s²

a = acceleration required = 2.13 m/s²

Therefore,

$F = (5000\ kg)(15.0093\ m/s^{2} + 2.13\ m/s^{2})\\$

<u>F = 85696.5 N = 85.69 KN</u>

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