Let c represent the weight of cashews and p the weight of pecans.

Then c + 10 = total weight of the nut mixture.

An equation for the value of the mixture follows:

$1.50(10 lb) + $0.75c = (c+10)($1.00)

Solve this equation for c: 15 + .75c = c + 10. Subtract .75c from both sides:

15 = 1c - 0.75c + 10. Then 5=0.25c, and c = 5/0.25, or 20.

Need 20 lb of cashews.

Check: the pecans weigh 10 lb and are worth $1.50 per lb, so the total value of the pecans is $15. The total value of the cashews is (20 lb)($0.75/lb), or $15. Does (20 lb + 10 lb)($1/lb) = $15 + $15? Yes. So c= 20 lb is correct.

3 0

2 years ago

Chapter 8 Written Homework 1. A hypothesis test is conducted to test the claim that the proportion of people with dark hair at M

UNO [17]

Answer:

we reject H₀

Step-by-step explanation: Se annex

The test is one tail-test (greater than)

Using α = 0,05 (critical value ) from z- table we get

z(c) = 1,64

And Test hypothesis is:

H₀ Null hypothesis μ = μ₀

Hₐ Alternate hypothesis μ > μ₀

Which we need to compare with z(s) = 2,19 (from problem statement)

The annex shows z(c), z(s), rejection and acceptance regions, and as we can see z(s) > z(c) and it is in the rejection region

So base on our drawing we will reject H₀

3 0

2 years ago

12 < k + 11 The solution of the inequality is (pls answer fast)

Free_Kalibri [48]

Answer:

Solve for K by simplifying both sides of the inequality, then isolating the variable.

Inequality Form:

k > 1

Interval Notation:

(1, ∞)

Step-by-step explanation:

4 0

2 years ago