Answer:
By pigeon hole principle, at least 2 subsets of A have same sum
Step-by-step explanation:
Let A = {x1, x2, . . . , x12} where i ≤ xi≤150
for any 6 element subset S of A, the sum of numbers in S is at least 6 since all integers are positive and it is at most 150+149+148+147+146+145= 885. so we consider number of pigeon holes = number of possible sums= 885 and number of pigeons = number of subsets of A of size 6= ¹²C₆= 924
Since number of pigeons is greater than number of pigeon holes, by pigeon hole principle, at least 2 subsets of A have same sum
E. none of them hope I helped
Hey there,
2 hours = 15 pages
1 hour = 15 / 2
= 7.5 pages
15 pages = $40
1 page = $40 / 15
= $2.666666666666667
7.5 pages= $2.666666666666667 x 7.5
= $20
Hope this helps :))
~Top
If MO bisects angle LMN:
6 x - 20 = 2 x + 36
6 x - 2 x = 36 + 20
4 x = 56
x = 56 : 4
x = 14
∠ LMN = 2 · ( 2 · 14 + 36 ) = 2 · ( 28 + 36 ) = 2 · 64 = 128
Answer : C ) x = 14, ∠ LMN = 128
Answer:
216
Step-by-step explanation:
You are rolling three die three times
a die has six sides
to obtain the sample space
we would have to multiply 6 x 6 x 6
which could account for the three roles which would be equivalent to the sample space
6^3