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3 years ago

Why don't we fan here pls help

Mathematics

1 answer:

In-s [12.5K]3 years ago

5 0

Answer:

1: C=615.75m

2: 62.83 meters or 60 meters rounded to the nearest tenth

Step-by-step explanation:

1: The circumference of a circle that has radius of 98 meters, using 3.14 for pi, is 615.75m.

Formula: C=2πr

C=2πr=2·π·98≈615.75216m

_______________________________________________

2: The difference in area between circle A and circle B, using 3.14 for pi and rounded to the nearest tenth is 62.83 meters or 60 meters.

<h3><u>Circle A:</u></h3>

The diameter of circle A is 12 cm.

Changing the diameter to radius is going to be easier.

Radius is half of the diameter.

12 ÷ 2 = 6

Therefore, the area of circle A is 113.1.

Formula: A=πr^2

A=πr^2=π·6^2≈113.09734

<h3><u>Circle B:</u></h3>

The diameter of circle B is 8 cm.

Once again, changing the diameter to radius is going to be easier.

Radius is half of the diameter.

8 ÷ 2 = 4

Therefore, the area of circle B is 50.27.

Formula: A=πr^2

A=πr2=π·42≈50.26548

113.09734 - 50.26548 = 62.83 meters or 60 meters.

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Answer:

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System #7, where x=3

System #5, where x=2

System #2, where x=1

Step-by-step explanation:

System #1: x=4

$2x+y=10\\x-3y=-2$

To solve, start by isolating your first equation for y.

$2x+y=10\\y=-2x+10$

Now, plug this value of y into your second equation.

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Isolate your second equation for y.

$2x+y=4\\y=-2x+4$

Plug this value of y into your first equation.

$x+2(-2x+4)=5\\x+(-4x)+8=5\\x-4x+8=5\\-3x=-3\\x=1$

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Isolate your first equation for y.

$5x+y=33\\y=-5x+33$

Plug this value of y into your second equation.

$x=18-4(-5x+33)\\x=18+20x-132\\-19x=-114\\x=6$

System #4: all real numbers (not included in your diagram)

$y=13-2x\\8x+4y=52$

Plug your value of y into your second equation.

$8x+4(13-2x)=52\\8x+52-8x=52\\0=0$

<em>all real numbers are solutions</em>

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Isolate your second equation for y.

$6x-y=11\\-y=-6x+11\\y=6x-11$

Plug in your value of y to your first equation.

$x+3(6x-11)=5\\x+18x-33=5\\19x=38\\x=2$

System #6: no solution (not included in your diagram)

$2x+y=10\\-6x-3y=-2$

Isolate your first equation for y.

$2x+y=10\\y=-2x+10$

Plug your value of y into your second equation.

$-6x-3(-2x+10)=-2\\-6x+6x-30=-2\\-30=-2$

<em>no solution</em>

System #7: x=3

$y=10+x\\2x+3y=45$

Plug your value of y into your second equation.

$2x+3(10+x)=45\\2x+30+3x=45\\5x=15\\x=3$

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Step-by-step explanation:

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