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goldenfox [79]
2 years ago
8

ASAP GIVING BRAINIEST AND 20 points 1. How can technology be both positive and negative when it comes to modified crops?

Mathematics
1 answer:
harkovskaia [24]2 years ago
6 0

Answer:

Technology can be both negative and positive when it comes to modified crops. It can be positive because it allows us to have more crops and resist pests and disease. It can be negative because it may cause deformities or health risks.

I really hope that helps you.

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Select the statement that describes this expression: 5 x 3 − (2 x 4) + 5.
Mashcka [7]

Answer:

It would be subtract the product of 2 and 4 from the product of 5 and 3, then add 5 because it’s parenthesis then you would multiply/devide then add/subtract whatever comes first

Step-by-step explanation:

5x3 - (2x4) + 5

5x3 - 8 + 5

15 - 8 + 5

7 + 5

12

(Hice los cálculos aquí en caso de que lo necesitaras)

3 0
3 years ago
Input in standard form the equation of the given line.
mario62 [17]
Use equation of line which passes through the 2 points A(x_1,y_1),B(x_2,y_2).

y-y_1= \frac{y_2-y_1}{x_2-x_1}(x-x_1) \\ \\A(1,5),B(-2,3)
\\ y-5= \frac{3-5}{-2-1}(x-1)
\\y-5= \frac{2}{3} (x-1)
\\y-5=\frac{2}{3}x-\frac{2}{3}
\\3y-15=2x-2
\\-2x+3y=-2+15
\\-2x+3y=13
5 0
3 years ago
Danielle needs to walk 4 miles.if she wants to reach her destination in 50 minutes ,how fast does she need to walk
Vika [28.1K]

Answer:

Step-by-step explanation:

Speed = distance/time

Speed = 50/4

Speed = 12.5

Your answer is C!!!

4 0
3 years ago
BRAINLIESTT ASAP! PLEASE HELP ME :)
Phoenix [80]

Answer:

20  

Step-by-step explanation:

ƒ(x) = 3x² – 2

g(x) = 4x + 2

1. Add the functions

By definition,  

(ƒ + g)(x) = ƒ(x) + g(x)

3x²          - 2

<u>       + 4x + 2 </u>

3x² + 4x

(ƒ + g)(x) = 3x² + 4x

2. Evaluate (ƒ + g)(2)

(ƒ + g)(2) = 3(2)² + 4(2) = 3(4) + 8 = 12 + 8 = 20

6 0
3 years ago
Read 2 more answers
The construction method used to construct a perpendicular through a point not on a line could also be used to construct a perpen
Rama09 [41]
The answer for the question above is TRUE.

Given a line segment with endpoints A and B, we must merely find a point on the perpendicular bisector of the line AB, then use the perpendicular line construction. To find the point on the perpendicular bisector, we must merely find a point that is equidistant from both A and B. We can do this with a compass by choosing a compass length greater than half the length AB, and then making an arc from A above the line AB. Then we make an arc from B having the same length. 

<span>Since we used the same length for each arc, the intersection of the arcs, P, is equidistant from A and B. Now we simply use the perpendicular line construction for line AB and P, which is off the line. This line will be a perpendicular bisector. </span>
6 0
3 years ago
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