Data are collected to see how many ice-cream cones are sold at a ballpark in a week. Day 1 is Sunday and Day 7 is the following
Saturday. Use the data from the table to create a scatter plot.
1 answer:
Step-by-step explanation:
Please find the attachment.
We have been given the data collected about the number of ice-cream cones sold at a ballpark in a week.
We are told that Day 1 corresponds to Sunday and Day 7 is following Saturday.
We can see from our given graph that horizontal axis represents the days from Sunday to Saturday and vertical axis shows the number of cones sold.
From given data we can see that on Sunday 25 and 26 cones were sold, so we just need to plot these points on our graph at (1,25) and (1,26).
On Monday no cones were sold.
On Tuesday 12 cones were sold, so we will add this point on graph at (3,12).
On Wednesday 8 and 10 cones were sold, so we just need to plot these points on our graph at (4,8) and (4,10).
There were 11 ice cream cones were sold on Thursday, so we will add this point on graph at (5,11).
On Friday 22 and 25 ice cream cones were sold, so we will plot these points on our graph at (6,22) and (6,25).
Similarly, we will graph ice-cream cones sold on Saturday at points (7,28) and (7,29).
Hence, we have created our scatter plot.
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Answer:
x = 2 1/3
Step-by-step explanation:
We can examine the equations to see where the solution lies.
<u>f(x) = (2/3) -x</u>
This has an x-intercept where y=0, at x=2/3. It has a y-intercept where x=0, at y=2/3. Its slope is -1.
<u>h(x) = 3 -2x</u>
This has an x-intercept where y=0, at x=3/2. It has a y-intercept where x=0, at y=3. Its slope is -2.
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In the first quadrant, the graph of h(x) is farther from the origin and steeper than the graph of f(x). The lines must cross in the 4th quadrant at some value of x that is greater than 3/2. The fraction in the definition of f(x) suggests that the solution will be a multiple of 1/3.
The attached table shows a couple of guesses at values of x that would make f(x) = h(x). We find that x = 7/3 is the solution we're looking for.
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<em>Additional comment</em>
Repetitive function evaluations are done conveniently and with fewer errors by a calculator or spreadsheet that can work with tables of values. Here, we have used a graphing calculator. These tools are readily available for free on almost any phone, tablet, or desktop computer platform.
