I Really need help, How do you solve this?

Mathematics

1 answer:

NikAS [45]3 years ago

7 0

Set up a proportion. (y-1)/6 = 5/3 then cross multiply to get 30 = 3y-3. add three and then divide by three to get y= 11. do the same process for X.

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A savings bank invests $58,800 in municipal bonds and earns 12% per year on the investment. How much money is earned per year?

seraphim [82]

To find the answer we simply have to find 12% of 58,800. So to do that, we can multiply it by .12

58,800 • .12 = 7,056

So $7,056 is earned per year

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3 years ago

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Translate each problem below into an equation and solve. Mr. Drysdale earned $906.25 in interest in one year on money that he ha

Effectus [21]

6.25% of $906.25 + $906.25

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3 years ago

Which expression uses the greatest common factor and distributive property to find 10+50?

Rudiy27

Ab+ac=a(b+c) where a is the greatest common factor
find greatest common factor of 10 and 50
10=1,2,5,10
50=1,2,5,10,25,50
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3 years ago

rory walks 62/24 of a mile to school,louise walkes 5/4 of a mile to school how much farther does rory walk

Digiron [165]

Rory walked 2/4 of a mile more than Louise.

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3 years ago

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Find a polynomial P(x) with real coefficients having a degree 4, leading coefficient 4, and zeros 3-i and 4i.

Alisiya [41]

now, this polynomial has roots of 3-i and 4i, namely 3 - i and 0 + 4i.

let's bear in mind that a complex root never comes all by her lonesome, her sibling is always with her, the conjugate, so if 3 - i is there, 3 + i is also coming along, likewise if 0 + 4i is there, her sibling 0 - 4i is also there.

$\bf \begin{cases} x=3-i\implies &x-3+i=0\\ x=3+i\implies &x-3-i=0\\ x=4i\implies &x-4i=0\\ x=-4i\implies &x+4i=0 \end{cases}\\\\[-0.35em] ~\dotfill\\\\ (x-3+i)(x-3-i)(x-4i)(x+4i)=\stackrel{y}{0} \\[2em] \underset{\textit{difference of squares}}{[(x-3)+i][(x-3)-i]}\underset{\textit{difference of squares}}{[x-4i][x+4i]}=0$

$\bf [(x-3)^2-i^2][x^2-(4i)^2]=y\implies [(x-3)^2-(-1)][x^2-(4^2i^2)]=0 \\[2em] [(x-3)^2-(-1)][x^2-(16(-1))]=0\implies [(x-3)^2+1][x^2+16]=0 \\[2em] [(x^2-6x+9)+1][x^2+16]=y\implies (x^2-6x+10)(x^2+16)=0 \\\\\\ x^4-6x^3+10x^2+16x^2-96x+160=0 \\\\\\ x^4-6x^3+26x^2-96x+160=0 \\\\\\ \stackrel{\textit{multiplying both sides by 4}}{4(x^4-6x^3+26x^2-96x+160)=4(0)} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill 4x^4-24x^3+104x^2-384x+640=y~\hfill$

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3 years ago