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bulgar [2K]
3 years ago
11

Jalen has 30 ounces of a solution that is made of up 30% acid and 70% water. How many ounces of water must Jalen add to this sol

ution to create a solution that is 20% acid and 80% water?
Mathematics
1 answer:
Ymorist [56]3 years ago
3 0
New volume of mixture
= 30%/20%*30 oz
= 45 oz
Jalen must therefore add (45-30)=15 oz of water.
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Leah loves chicken wings and is comparing the deals at three different restaurants. Buffalo Bills has 888 wings for \$7$7dollar
ella [17]

Cost of chicken wings at Buffalo Bills = 8 wings for $7

Cost of 1 wing at Buffalo Bills = \frac{7}{8} =0.875

Cost of chicken wings at Buffalo Mild Wings = 12 wings for $10

Cost of 1 wing at Buffalo Mild Wings = \frac{10}{12}= 0.833

Cost of chicken wings at Wingers = 20 wings at $17

Cost of 1 wing at Wingers = \frac{17}{20}= 0.850

Hence, comparing all the three costs per wing, we can see that Buffalo Mild Wings is serving chicken wings at lowest price of $0.833 per wing.

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3 years ago
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Sunny_sXe [5.5K]

Answer:

From the chapter Playing with numbers

we can define derek has 2×10^2 + 7 × 10^1 + 7× +0^0

as If ABC a number then ABC can be written as 10^2A+10^1B+10^0C

Hope it helps

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3 years ago
Please help me quick im giving a lot for this!
Lady_Fox [76]

Answer:

The answer is D!!

Step-by-step explanation:

Hope this helps!! ;)

Here is a scary story for all!! Enjoy!!

The Ghost Man

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5 0
3 years ago
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15x^2 + 41x + 28 <br><br>STEP BY STEP ANSWER PLSSS​
maria [59]

Answer:

(3x+4)(5x+7)

Step-by-step explanation:

15x^2 +41x+28

Factor the expression by grouping. First, the expression needs to be rewritten as 15x^2 +ax+bx+28. To find a and b, set up a system to be solved.

a+b=41

ab=15×28=420

Since ab is positive, a and b have the same sign. Since a+b is positive, a and b are both positive. List all such integer pairs that give product 420.

1,420

2,210

3,140

4,105

5,84

6,70

7,60

10,42

12,35

14,30

15,28

20,21

Calculate the sum for each pair.

1+420=421

2+210=212

3+140=143

4+105=109

5+84=89

6+70=76

7+60=67

10+42=52

12+35=47

14+30=44

15+28=43

20+21=41

The solution is the pair that gives sum 41.

a=20

b=21

Rewrite 15x^2 +41x+28 as (15x^2 +20x)+(21x+28).

(15x^2 +20x)+(21x+28)

Factor out 5x in the first and 7 in the second group.

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Factor out common term 3x+4 by using distributive property.

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3 years ago
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Answer:

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4 0
3 years ago
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