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4 years ago

What's all the names that apply to a rhombus

Mathematics

1 answer:

dimaraw [331]4 years ago

5 0

Rhombus rectangle quadrilateral quadrangle shape (idk abt that one) polygon

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y dos my messaging system not working i cant send to people but it says I'm not getting anything and it says i need to answer mo

kogti [31]

Answer:

You need to answer 1000 questions first. I honestly think it's stupid.

Step-by-step explanation:

6 0

3 years ago

Find the coordinates of the midpoint of UV with endpoints U(2, −6) and V(5, 3).

seraphim [82]

I’m so sorry I really don’t know the answer but try the internet

4 0

3 years ago

Given the preimage and image, find the dilation scale factor

77julia77 [94]

Given:

The preimage and image of a triangle in the given figure.

To find:

The dilation scale factor.

Solution:

From the given figure it is clear that the vertices of the triangle ABC are A(-2,-2), B(-1,2) and C(2,1).

The vertices of the triangle A'B'C' are A'(-4,-4), B'(-2,4) and C'(4,2).

If a figure is dilated by factor K with (0,0) as the center of dilation, then

$(x,y)\to (kx,ky)$

Let the scale factor be K, then the image of point A is:

$A(-2,-2)\to A'(k(-2),k(-2))$

$A(-2,-2)\to A'(-2k,-2k)$

From the given figure it is clear that the image of point A is A'(-4,-4).

$A'(-2k,-2k)=A'(-4,-4)$

On comparing both sides, we get

$-2k=-4$

$k=\dfrac{-4}{-2}$

$k=2$

Therefore, the dilation scale factor is 2.

8 0

3 years ago

What two positive real numbers whose product is 21 have the smallest possible sum?

GalinKa [24]

Answer:

$x=\sqrt{21}$

$y=\sqrt{21}$

Step-by-step explanation:

Let x and y are the two positive real numbers

product of two numbers is 21

$x y=21$

$y=\frac{21}{x}$

The sum of the two numbers is f(x) =x+y

Replace y with 21/x

$f(x) =x+\frac{21}{x}$

we need to find smallest possible sum , so we take derivative using power rule

$f'(x)= 1-\frac{21}{x^2}$

when sum is minimum then the derivative is equal to 0

$0= 1-\frac{21}{x^2}$

$0=\frac{x^2-21}{x^2}$

multiply both sides by x^2

$x^2-21=0$

$x^2=21$

Take square root on both sides

$x=\sqrt{21}$

$y=\frac{21}{x}$

$y=\frac{21}{\sqrt{21}}$

$y=\sqrt{21}$

3 0

4 years ago

Calculate the distance between (4,9) and (-2,6) using the distance formula.

MAVERICK [17]

Answer:

$\large\boxed{d=3\sqrt5}$

Step-by-step explanation:

$\text{the formula of a distance between two points}\ A(x_1,\ y_1)\ \text{and}\ B(x_2,\ y_2):\\\\|AB|=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\=========================\\\\\text{We have}\ (4,\ 9)\ \text{and}\ (-2,\ 6).\ \text{Substitute:}\\\\d=\sqrt{(-2-4)^2+(6-9)^2}=\sqrt{(-6)^2+(-3)^2}=\sqrt{36+9}=\sqrt{45}\\\\\sqrt{45}=\sqrt{9\cdot5}=\sqrt9\cdot\sqrt5=3\sqrt5$

6 0

3 years ago