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Papessa [141]
3 years ago
7

A ball with a potential energy of 7500 J is at the top of a hill. The ball weighs 500 N, what is the height of the ball?

Mathematics
1 answer:
seropon [69]3 years ago
8 0

Answer:

yerp

Step-by-step explanation:

gv5eby5evfcqwcevwrybe4v

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Answer:

53°

Step-by-step explanation:

It is given that the total measurement of the two angles combined would equate to 116°.

It is also given that m∠WXY is 10° more then m∠ZXY.

Set the system of equation:

m∠1 + m∠2 = 116°

m∠1 = m∠2 + 10°

First, plug in "m∠2 + 10" for m∠1 in the first equation:

m∠1 + m∠2 = 116°

(m∠2 + 10) + m∠2 = 116°

Simplify. Combine like terms:

2(m∠2) + 10 = 116

Next, isolate the <em>variable</em>, m∠2. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS.

First, subtract 10 from both sides of the equation:

2(m∠2) + 10 (-10) = 116 (-10)

2(m∠2) = 116 - 10

2(m∠2) = 106

Next, divide 2 from both sides of the equation:

(2(m∠2))/2 = (106)/2

m∠2 = 106/2 = 53°

53° is your answer.

~

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