The easiest way to do this is to plug in the numbers for the variebles and see if they equal the same in both sides. lets try the first one 5(1)+2(-3)=-1, multiply the nmbers to get 5-6=-1 now simplify to get the answer of -1=-1, they both equal the same so this means that the first option is the correct one
Hope this helps
The area of a rhombus is half of the product of the lengths of the diagonals.
area = (7.5 yd + 7.5 yd)(13 yd + 13 yd)/2
area = (15 yd)(26 yd)/2
area = 390 yd^2/2
area = 195 yd^2
Answer: 195
It looks like your equations are
7M - 2t = -30
5t - 12M = 115
<u>Solving by substitution</u>
Solve either equation for one variable. For example,
7M - 2t = -30 ⇒ t = (7M + 30)/2
Substitute this into the other equation and solve for M.
5 × (7M + 30)/2 - 12M = 115
5 (7M + 30) - 24M = 230
35M + 150 - 24M = 230
11M = 80
M = 80/11
Now solve for t.
t = (7 × (80/11) + 30)/2
t = (560/11 + 30)/2
t = (890/11)/2
t = 445/11
<u>Solving by elimination</u>
Multiply both equations by an appropriate factor to make the coefficients of one of the variables sum to zero. For example,
7M - 2t = -30 ⇒ -10t + 35M = -150 … (multiply by 5)
5t - 12M = 115 ⇒ 10t - 24M = 230 … (multiply by 2)
Now combining the equations eliminates the t terms, and
(-10t + 35M) + (10t - 24M) = -150 + 230
11M = 80
M = 80/11
It follows that
7 × (80/11) - 2t = -30
560/11 - 2t = -30
2t = 890/11
t = 445/11
Answer:
64 i hope im right
Step-by-step explanation:
