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IRINA_888 [86]
3 years ago
13

write an equation in slope-intercept form for the line that passes through (-2,5) and is perpendicular to the line described by

y=-2x+6
Mathematics
1 answer:
Rama09 [41]3 years ago
4 0

Answer:

<h2>         y = ¹/₂x + 6</h2>

Step-by-step explanation:

The product of slopes of perpendicular lines is -1

y = - 2x + 6  ⇒   m₁ = - 2

m₁m₂ = -1

-2m₂ = -1

m₂ = ⁻¹/₋₂ = ¹/₂

The Point-Slope form of equation of a line with slope of "m" and passing through point (x₁, y₁) is:  y - y₁ = m(x - x₁)

m = ¹/₂

(-2, 5)  ⇒  x₁ = -2,  y₁ = 5

So the equation in point-slope form:

                                                  y - 5 = ¹/₂(x - (-2))

Therefore:

y - 5 = ¹/₂x + 1

y = ¹/₂x + 1 + 5

<h3>y = ¹/₂x + 6</h3>
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