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IRINA_888 [86]
3 years ago
13

write an equation in slope-intercept form for the line that passes through (-2,5) and is perpendicular to the line described by

y=-2x+6
Mathematics
1 answer:
Rama09 [41]3 years ago
4 0

Answer:

<h2>         y = ¹/₂x + 6</h2>

Step-by-step explanation:

The product of slopes of perpendicular lines is -1

y = - 2x + 6  ⇒   m₁ = - 2

m₁m₂ = -1

-2m₂ = -1

m₂ = ⁻¹/₋₂ = ¹/₂

The Point-Slope form of equation of a line with slope of "m" and passing through point (x₁, y₁) is:  y - y₁ = m(x - x₁)

m = ¹/₂

(-2, 5)  ⇒  x₁ = -2,  y₁ = 5

So the equation in point-slope form:

                                                  y - 5 = ¹/₂(x - (-2))

Therefore:

y - 5 = ¹/₂x + 1

y = ¹/₂x + 1 + 5

<h3>y = ¹/₂x + 6</h3>
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What’s the mean,median,mode and range
Komok [63]

Answer:

Mean=2.1

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Step-by-step explanation:

Mean is all the numbers added up and then divided by the amount of numbers there are, so 0+1+0+2+3+1+3+5+4+2=21, and then 21 divided by 10=2.1

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3 years ago
If a certain machine makes electrical resistors having a mean resistance of 40 ohms and a standard deviation of 2 ohms, what is
V125BC [204]

Answer:

The probability is  P(\= X  <  40.4) = 0.84134

Step-by-step explanation:

From the question we are told that

   The mean is  \mu =40 \ \Omega

   The standard deviation is  \sigma  = 2 \ \Omega

   The sample size is  n = 25

    The combined resistance is   \sum x_i = 1010 \ \Omega

Generally the sample mean is mathematically represented as

      \= x  = \frac{\sum x_i }{n}

=>   \= x  = \frac{1010 }{25}

=>   \= x  = 40.4 \ \Omega

Generally the standard error of the mean is mathematically represented as

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=>  \sigma_{x} = 0.4

Generally the probability that a random sample of 25 of these resistors will have a combined resistance of less than 1010 ohms is mathematically represented as

       P(\= X  <  40.4) = P( \frac{\= X - \mu }{\sigma_{x }} <  \frac{ 40.4 - 40 }{0.4}  )

\frac{\= X -\mu}{\sigma }  =  Z (The  \ standardized \  value\  of  \ \= X )

    P(\= X  <  40.4) = P( Z <  1 )

From the z table  the area under the normal curve to the left corresponding to  1 is

     P(\= X  <  40.4) = P( Z <  1 ) = 0.84134

     P(\= X  <  40.4) = 0.84134

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