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lesya [120]
3 years ago
11

Find the equation of the line that is perpendicular to 3y-x=7 and passes through the point (2,-1

Mathematics
1 answer:
boyakko [2]3 years ago
7 0
Hello
<span>an equation for the line in​ point-slope form and general form is :
y = ax+b   a : </span>slope  ; the <span>Passing through (x' ; y')
</span>y' = ax'+b 
y-y' =a(x-x')      and : x' =2   y' = - 1
calculate a :
let :  y = ax+b .....(D)
   ....<span>3y-x=7</span>....(D') or  y = (1/3)x+7/3
.(D) perpendicular to(D') : slope (D) × slope (D') = -1 

 slope (D') = 1/3
slop(D)×(1/3) = -1
slope (D) = -3
equation for the line    :   y-y' =a(x-x') 
y+1 =(-3) (x-2)
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