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iogann1982 [59]
3 years ago
5

A) Expand and simplify (4x + 3)(2x - 5)

Mathematics
2 answers:
Delicious77 [7]3 years ago
6 0

Answer:

8x² - 14x - 15

Step-by-step explanation:

(4x + 3)(2x - 5)

8x² - 20x + 6x - 15

8x² - 14x - 15

alina1380 [7]3 years ago
3 0

Answer:

Step-by-step explanation:

Use FOIL, first outside inside last.

4x*2x - 5*4x + 3*2x - 3*5

8x^2-20x+6x-15\\8x^2-14x-15\\

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A new bean company is working on designing its label for the can. If the can measures 4 inches in height and has a 3 inch diamet
Arlecino [84]

Answer: 37.68 square inches of paper

Step-by-step explanation:

Hi to answer this question we have to calculate the side area (since the label doesn't cover the top and bottom area)

First, we have to find the circumference.

Circumference (C) = 2 π r

Since:  

Diameter = 2 radius

3 = 2r

3/2 =r

r =1.5 inches

Back with the circumference formula

Replacing with the values given:

C = 2 (3.14) 1.5

C= 9.42

Side area = C x heigth = 9.42 x 4 = 37.68 square inches  

4 0
3 years ago
What’s the answer to this question. <br> Simple correct answers
Sophie [7]

Answer:

1st one

Step-by-step explanation:

5 0
4 years ago
What is the sum of 1 1/2 and 2/3
prisoha [69]

1\dfrac{1}{2}+\dfrac{2}{3}=1+\dfrac{1\cdot3}{2\cdot3}+\dfrac{2\cdot2}{3\cdot2}=1+\dfrac{3}{6}+\dfrac{4}{6}=1+\dfrac{3+4}{6}=1+\dfrac{7}{6}=1+1\dfrac{1}{6}=2\dfrac{1}{6}\\\\Answer:\ \boxed{1\dfrac{1}{2}+\dfrac{2}{3}=2\dfrac{1}{6}}

6 0
3 years ago
Read 2 more answers
A square piece of paper has an area of 36 square inches what is the perimeter of the paper​
Gekata [30.6K]

Lets represent the side of the square as s , since we know the area is 36. write s

{s}^{2}  = 36

s = \sqrt{36}

the square root of 36 is 6. So, we know the side is 6. The formula for perimeter is P= s+s+s+s , but since it is a square and all the sides are equal, for a perimeter of a square you can do p= 4s , now substitute 6 for s to get 4(6)=24 so the perimeter of a square would be 24 inches

6 0
3 years ago
HELP ASAP
Naily [24]

Answer:

y+4 = -\frac{1}{3} (x-1)

Step-by-step explanation:

1) First, find the slope of the line. Use the slope formula m = \frac{y_2-y_1}{x_2-x_1} to find the slope. Substitute the x and y values of the given points into the formula and solve:

m = \frac{(-5)-(-4)}{(4)-(1)} \\m = \frac{-5+4}{4-1} \\m = \frac{-1}{3}

So, the slope is -\frac{1}{3}.

2) Use the point-slope formula y-y_1  = m (x-x_1) to write the equation of the line in point-slope form. Substitute values for m, x_1, and y_1 into the formula.

Since m represents the slope, substitute -\frac{1}{3}  in its place. Since x_1 and y_1 represent the x and y values of one point on the line, choose any one of the given points (it doesn't matter which one) and substitute the x and y values of it into the formula. (I chose (1,-4), as seen below). This gives the equation of the line in point-slope form.    

y-(-4) = -\frac{1}{3} (x-(1))\\y+4 = -\frac{1}{3} (x-1)

5 0
3 years ago
Read 2 more answers
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