The correct choices to fill the blanks are listed below:
- AD
- BC
- AC
- CBA
- angle BAC
- CD
<h3>
How to prove that a quadrilateral is a parallelogram</h3>
In this question we should fill the blanks based all information related to Euclidean geometry, especially concepts related to angles, triangles, parallelism and quadrilaterals.
The complete paragraph is shown below:
<em>Since </em><u><em>AD</em></u><em> is parallel to </em><u><em>BC</em></u><em>, alternate interior angles. </em>
<u><em>AD</em></u><em> and </em><u><em>BC</em></u><em> are congruent. </em>
<em>AC is congruent to </em><u><em>AC</em></u><em> since segments are congruent to themselves.</em>
<em>Along with the given information that AD is congruent to BC, triangle ADC is congruent to triangle </em><u><em>CBA</em></u><em> by the Side-Angle-Side Triangle Congruence. </em>
<em>Since the triangles are congruent, all pairs of corresponding angles are congruent, so angle DCA is congruent to </em><u><em>angle BAC</em></u><em>.</em>
<em>Since those alternate interior angles are congruent. AB must be parallel to </em><u><em>CD</em></u><em>. </em>
<em>Since we define a parallelogram as a quadrilateral with both pairs of opposite sides parallel, ABCD is a parallelogram.</em>
To learn more on quadrilaterals, we kindly invite to check this verified question: brainly.com/question/25240753
