There is sufficient statistical evidence to prove that the standard deviation of the technology-related workers and the standard deviation of the non-technology workers are equal.

Step-by-step explanation:

Here we have our null hypothesis as H₀: σ² = s²

Our alternative hypothesis is then Hₐ: σ² ≠ s²

We therefore have a two tailed test

To test the hypothesis of difference in standard deviation which is the Chi squared test given as follows

$\chi ^{2} = \dfrac{\left (n-1 \right )s^{2}}{\sigma ^{2}}$

Where:

n = Size of sample

s² = Variance of sample = 950²

σ² = Variance of population = 650²

Degrees of freedom = n - 1 = 71 - 1 = 70

α = Significance level = 0.1

Therefore, we use 1 - 0.1 = 0.9

From the Chi-square table, we have the critical value as

1 - α/2 = 51.739,

α/2 = 90.531

Plugging the values in the above Chi squared test equation, we have;

$\chi ^{2} = \dfrac{\left (23-1 \right )950^{2}}{650 ^{2}} = 49.994$

Therefore, since the test value within the critical region, we do not reject the null hypothesis, hence there is sufficient statistical evidence to prove that the standard deviation of the technology-related workers and the standard deviation of the non-technology workers are equal.

6 0

3 years ago

Which of the following refers to the principle that if A exceeds B in some property and B exceeds C, then A must also exceed C?

Mazyrski [523]

Answer:

Option c) Transitivity

Step-by-step explanation:

We are given the following information in the question:

If A exceeds B in some property and B exceeds C, then A must also exceed C.

We have to define the property shown by A,B and C.

Transitivity:

It is a mathematical property which states that between three numbers if first and second share the property, second and third share the property, then according to transitive property, the property holds between first and third as well.

Thus, A, B and C here shows the transitive property.

The correct answer is

Option c) Transitivity

7 0

4 years ago