PLZ HELP!!! A Circle has a radius of 6x9y5 Cm.

Mathematics

1 answer:

frosja888 [35]2 years ago

4 0

To solve this exercise, you must follow the proccedure below:

1. You have that:

- The formula for calculate the area of the circle is: A=πr² ("r" is the radius of the circle).
-The problem says that the circle has a radius of 6x^9y^5 (r=6x^9y^5)

2. When you substitute r=6x^9y^5 into A=πr², you obtain:

A=πr²
A=π(6x^9y^5 cm)²

3. By applying the exponents properties, you have:

A=36πx^18y^10 cm²

4. Therefore, the answer is the second option: 36πx^18y^10

You might be interested in

Faction help plz!!!!

Marizza181 [45]

Complete 2/3 x the number of plates

6 0

2 years ago

A rectangular box has length 20cm, width 6cm and height 4cm. find how many cubes of size 2cm that will fit into the box.

Papessa [141]

Answer:

$\boxed{\pink{\sf The \ number \ of \ cubes \ that \ can \ be \ fitted \ is 60 .}}$

Step-by-step explanation:

Given dimensions of the box = 20cm × 6cm × 4cm .

Dimension of the cube = 2cm × 2cm × 2cm .

Therefore the number of cubes that can be fitted into the box will be equal to the Volume of box divided by the Volume of the cube. So ,

$\boxed{\red{\bf \implies No. \ of \ cubes \ = \dfrac{Volume \ of \ box}{Volume \ of \ cube }}}$

$\bf \implies n_{cubes} = \dfrac{20cm \times 6cm \times 4cm .}{2cm \times 2cm \times 2cm } \\\\\bf\implies n_{cubes} = 10 \ times 3cm \times 2cm \\\\\implies \boxed{\bf n_{cubes}= 60 }$

<h3>Hence the number of cubes that can be fitted in the box is 60 .</h3>

6 0

3 years ago

What is 6 more than 7 times a number is 41

son4ous [18]

the problem would be set up as 6+(7*x)=41

first u take off the number 6 by subtracting it from itself to cancel it out then u do the same to the number 41

7x =41 now u need to cancel out the number 7 attatched to the x so u divikde it by itself and then do the same to the other side so 41 divided by 7 =5.9

so x =5.9

8 0

3 years ago

S Rob and Bob together scored 88

Paul [167]

Rob scored 34 points. 88-54=34

3 0

3 years ago

Solve the system of linea 1. y=x y=2x - 11

aksik [14]

$\left \{ {{y=x} \atop {y=2x-11}} \right. \\x=2x-11\\x=11\\\\y=x\\y=11\\\\\\Answer: (11;11)$